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compositor: Clarify if view is in a layer

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As seen in some instances, subsurfaces do not have an entry in their
layer_link, as we bring them into existence rather directly in  the
view_list and not using the layer list approach.

This adds two messages to the debug scene graph to point out if the
views aren't really in any layer or if they're indirectly in the view
list using an ancestor (the main parent view actually).

Signed-off-by: Marius Vlad <marius.vlad@collabora.com>
This commit is contained in:
Marius Vlad 2022-09-14 12:03:14 +03:00
parent f31c81dce7
commit e96494801b
1 changed files with 6 additions and 0 deletions
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6
libweston/compositor.c
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@ -7896,6 +7896,12 @@ debug_scene_view_print(FILE *fp, struct weston_view *view, int view_idx)
fprintf(fp, "\t[view is not mapped!]\n");
if (!weston_surface_is_mapped(view->surface))
fprintf(fp, "\t[surface is not mapped!]\n");
if (wl_list_empty(&view->layer_link.link)) {
if (!get_view_layer(view))
fprintf(fp, "\t[view is not part of any layer]\n");
else
fprintf(fp, "\t[view is under parent view layer]\n");
}
box = pixman_region32_extents(&view->transform.boundingbox);
fprintf(fp, "\t\tposition: (%d, %d) -> (%d, %d)\n",