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libinput: Only forward first and last press and release for a button

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Pointer button events will be received from a device where a button has
been pressed, even though an equivalent button has been pressed (same
button code) on a device connected to the same seat. notify_button()
expects to only be called as if there was only one pointer device
associated with the given seat, so to achieve this, ignore every event
where forwarding it would result in multiple 'pressed' or 'released'
notifications.

Signed-off-by: Jonas Ådahl <jadahl@gmail.com>
Reviewed-by: Peter Hutterer <peter.hutterer@who-t.net>
Reviewed-by: Daniel Stone <daniels@collabora.com>
This commit is contained in:
Jonas Ådahl 2015-01-30 12:22:59 +08:00 committed by Bryce Harrington
parent 6b4b24155f
commit e90b9e9b59
1 changed files with 11 additions and 0 deletions
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11
src/libinput-device.c
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@ -119,6 +119,17 @@ handle_pointer_button(struct libinput_device *libinput_device,
{
struct evdev_device *device =
libinput_device_get_user_data(libinput_device);
int button_state =
libinput_event_pointer_get_button_state(pointer_event);
int seat_button_count =
libinput_event_pointer_get_seat_button_count(pointer_event);
/* Ignore button events that are not seat wide state changes. */
if ((button_state == LIBINPUT_BUTTON_STATE_PRESSED &&
seat_button_count != 1) ||
(button_state == LIBINPUT_BUTTON_STATE_RELEASED &&
seat_button_count != 0))
return;
notify_button(device->seat,
libinput_event_pointer_get_time(pointer_event),