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cryptenroll: merge two if checks with same condition
This removes a duplicate condition check by adding a common surrounding if block. This also change a confusing if check: "(X && Y) && Z" to simply "X && Y && Z"
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@ -467,16 +467,18 @@ static int parse_argv(int argc, char *argv[]) {
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}
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}
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if ((arg_enroll_type == ENROLL_FIDO2 && arg_unlock_type == UNLOCK_FIDO2)
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&& !(arg_fido2_device && arg_unlock_fido2_device))
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return log_error_errno(SYNTHETIC_ERRNO(EINVAL),
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"When both enrolling and unlocking with FIDO2 tokens, automatic discovery is unsupported. "
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"Please specify device paths for enrolling and unlocking respectively.");
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if (arg_enroll_type == ENROLL_FIDO2) {
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if (arg_enroll_type == ENROLL_FIDO2 && !arg_fido2_device) {
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r = fido2_find_device_auto(&arg_fido2_device);
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if (r < 0)
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return r;
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if (arg_unlock_type == UNLOCK_FIDO2 && !(arg_fido2_device && arg_unlock_fido2_device))
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return log_error_errno(SYNTHETIC_ERRNO(EINVAL),
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"When both enrolling and unlocking with FIDO2 tokens, automatic discovery is unsupported. "
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"Please specify device paths for enrolling and unlocking respectively.");
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if (!arg_fido2_device) {
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r = fido2_find_device_auto(&arg_fido2_device);
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if (r < 0)
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return r;
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}
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}
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if (optind >= argc)
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