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AK: Make Optional<T> explicitly constructible from Optional<U>
As long as T is constructible from U. This allows us to avoid patterns like `abc.has_value() ? Optional<U>(abc.value()) : Optional<U>()`.
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@ -24,6 +24,9 @@ namespace AK {
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template<typename T>
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class [[nodiscard]] Optional {
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template<typename U>
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friend class Optional;
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public:
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using ValueType = T;
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@ -50,17 +53,31 @@ public:
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#endif
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: m_has_value(other.m_has_value)
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{
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if (other.has_value()) {
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if (other.has_value())
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new (&m_storage) T(other.value());
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}
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}
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ALWAYS_INLINE Optional(Optional&& other)
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: m_has_value(other.m_has_value)
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{
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if (other.has_value()) {
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if (other.has_value())
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new (&m_storage) T(other.release_value());
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}
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template<typename U>
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requires(IsConstructible<T, U const&> && !IsSpecializationOf<T, Optional> && !IsSpecializationOf<U, Optional>) ALWAYS_INLINE explicit Optional(Optional<U> const& other)
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: m_has_value(other.m_has_value)
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{
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if (other.has_value())
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new (&m_storage) T(other.value());
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}
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template<typename U>
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requires(IsConstructible<T, U&&> && !IsSpecializationOf<T, Optional> && !IsSpecializationOf<U, Optional>) ALWAYS_INLINE explicit Optional(Optional<U>&& other)
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: m_has_value(other.m_has_value)
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{
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if (other.has_value())
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new (&m_storage) T(other.release_value());
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}
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}
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template<typename U = T>
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