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JsonValue: No need to null-check StringImpls if type is Type::String.

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If you try to create a JsonValue from a null String(), it will become a
null JsonValue anyway.
This commit is contained in:
Andreas Kling 2019-06-29 12:03:53 +02:00
parent 50677a58d4
commit 7f224ade60
1 changed files with 4 additions and 3 deletions
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7
AK/JsonValue.cpp
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@ -31,8 +31,9 @@ void JsonValue::copy_from(const JsonValue& other)
m_type = other.m_type;
switch (m_type) {
case Type::String:
ASSERT(!m_value.as_string);
m_value.as_string = other.m_value.as_string;
AK::ref_if_not_null(m_value.as_string);
m_value.as_string->ref();
break;
case Type::Object:
m_value.as_object = new JsonObject(*other.m_value.as_object);
@ -105,7 +106,7 @@ JsonValue::JsonValue(const String& value)
} else {
m_type = Type::String;
m_value.as_string = const_cast<StringImpl*>(value.impl());
AK::ref_if_not_null(m_value.as_string);
m_value.as_string->ref();
}
}
@ -125,7 +126,7 @@ void JsonValue::clear()
{
switch (m_type) {
case Type::String:
AK::deref_if_not_null(m_value.as_string);
m_value.as_string->deref();
break;
case Type::Object:
delete m_value.as_object;