configure: Add -Werror to PIE probe

Without -Werror, the probe may succeed, but then compilation fails
later when -Werror is added for other reasons.  Shows up on windows,
where the compiler complains about -fPIC.

Signed-off-by: Richard Henderson <richard.henderson@linaro.org>
Signed-off-by: Alex Bennée <alex.bennee@linaro.org>
Reviewed-by: Philippe Mathieu-Daudé <philmd@redhat.com>
Tested-by: Philippe Mathieu-Daudé <philmd@redhat.com>
Message-Id: <20200401214756.6559-1-richard.henderson@linaro.org>
Message-Id: <20200403191150.863-13-alex.bennee@linaro.org>
This commit is contained in:
Richard Henderson 2020-04-03 20:11:50 +01:00 committed by Alex Bennée
parent 58d5e749d6
commit eca7a8e6c0

4
configure vendored
View file

@ -2119,7 +2119,7 @@ if compile_prog "-Werror -fno-pie" "-no-pie"; then
fi
if test "$static" = "yes"; then
if test "$pie" != "no" && compile_prog "-fPIE -DPIE" "-static-pie"; then
if test "$pie" != "no" && compile_prog "-Werror -fPIE -DPIE" "-static-pie"; then
QEMU_CFLAGS="-fPIE -DPIE $QEMU_CFLAGS"
QEMU_LDFLAGS="-static-pie $QEMU_LDFLAGS"
pie="yes"
@ -2132,7 +2132,7 @@ if test "$static" = "yes"; then
elif test "$pie" = "no"; then
QEMU_CFLAGS="$CFLAGS_NOPIE $QEMU_CFLAGS"
QEMU_LDFLAGS="$LDFLAGS_NOPIE $QEMU_LDFLAGS"
elif compile_prog "-fPIE -DPIE" "-pie"; then
elif compile_prog "-Werror -fPIE -DPIE" "-pie"; then
QEMU_CFLAGS="-fPIE -DPIE $QEMU_CFLAGS"
QEMU_LDFLAGS="-pie $QEMU_LDFLAGS"
pie="yes"