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openpic: don't crash on a register access without a CPU context
If we access a register via the QEMU memory inspection commands (e.g. "xp") rather than from guest code, we won't have a CPU context. Gracefully fail to access the register in that case, rather than crashing. Signed-off-by: Scott Wood <scottwood@freescale.com> Signed-off-by: Alexander Graf <agraf@suse.de>
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parent
a26a7b3833
commit
c3203fa5b2
1 changed files with 15 additions and 1 deletions
16
hw/openpic.c
16
hw/openpic.c
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@ -161,7 +161,11 @@ static inline int test_bit(uint32_t *field, int bit)
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static int get_current_cpu(void)
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{
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return cpu_single_env->cpu_index;
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if (!cpu_single_env) {
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return -1;
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}
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return cpu_single_env->cpu_index;
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}
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static uint32_t openpic_cpu_read_internal(void *opaque, hwaddr addr,
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@ -810,6 +814,11 @@ static void openpic_cpu_write_internal(void *opaque, hwaddr addr,
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DPRINTF("%s: cpu %d addr " TARGET_FMT_plx " <= %08x\n", __func__, idx,
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addr, val);
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if (idx < 0) {
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return;
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}
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if (addr & 0xF)
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return;
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dst = &opp->dst[idx];
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@ -875,6 +884,11 @@ static uint32_t openpic_cpu_read_internal(void *opaque, hwaddr addr,
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DPRINTF("%s: cpu %d addr " TARGET_FMT_plx "\n", __func__, idx, addr);
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retval = 0xFFFFFFFF;
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if (idx < 0) {
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return retval;
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}
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if (addr & 0xF)
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return retval;
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dst = &opp->dst[idx];
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