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user_only: compile everything with -fpie

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We really need compile _all_ sources for user target with -fpie when
use --enable-user-pie.

It's regression introduced by commit add16157d7.

Signed-off-by: Kirill A. Shutemov <kirill@shutemov.name>
Cc: Blue Swirl <blauwirbel@gmail.com>
Signed-off-by: Juan Quintela <quintela@redhat.com>
Signed-off-by: Blue Swirl <blauwirbel@gmail.com>
This commit is contained in:
Kirill A. Shutemov 2009-12-19 15:16:08 +00:00 committed by Blue Swirl
parent 060fbfe1d6
commit 299060a06e
2 changed files with 9 additions and 1 deletions
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7
Makefile.user
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@ -2,10 +2,15 @@
include ../config-host.mak
include $(SRC_PATH)/rules.mak
include config.mak
.PHONY: all
VPATH=$(SRC_PATH)
# Do not take %.o from $(SRC_PATH), only %.c and %.h
# All %.o for user targets should be built with -fpie, when
# configured with --enable-user-pie, so we don't want to
# take %.o from $(SRC_PATH), since they built without -fpie
vpath %.c %.h $(SRC_PATH)
QEMU_CFLAGS+=-I..

3
configure vendored
View file

@ -2652,3 +2652,6 @@ d=libuser
mkdir -p $d
rm -f $d/Makefile
ln -s $source_path/Makefile.user $d/Makefile
if test "$static" = "no" -a "$user_pie" = "yes" ; then
echo "QEMU_CFLAGS+=-fpie" > $d/config.mak
fi