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64870feebe
A convoluted test case for iterators convergence logic that demonstrates that states with branch count equal to 0 might still be a part of not completely explored loop. E.g. consider the following state diagram: initial Here state 'succ' was processed first, | it was eventually tracked to produce a V state identical to 'hdr'. .---------> hdr All branches from 'succ' had been explored | | and thus 'succ' has its .branches == 0. | V | .------... Suppose states 'cur' and 'succ' correspond | | | to the same instruction + callsites. | V V In such case it is necessary to check | ... ... whether 'succ' and 'cur' are identical. | | | If 'succ' and 'cur' are a part of the same loop | V V they have to be compared exactly. | succ <- cur | | | V | ... | | '----' Signed-off-by: Eduard Zingerman <eddyz87@gmail.com> Link: https://lore.kernel.org/r/20231024000917.12153-7-eddyz87@gmail.com Signed-off-by: Alexei Starovoitov <ast@kernel.org> |
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crypto/chacha20-s390 | ||
cxl | ||
fault-injection | ||
ktest | ||
kunit | ||
memblock | ||
nvdimm | ||
radix-tree | ||
scatterlist | ||
selftests | ||
vsock |