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bpf: Use struct_size()

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Use struct_size() instead of hand writing it.
This is less verbose and more robust.

Signed-off-by: Andy Shevchenko <andriy.shevchenko@linux.intel.com>
Signed-off-by: Andrii Nakryiko <andrii@kernel.org>
Acked-by: Yonghong Song <yonghong.song@linux.dev>
Link: https://lore.kernel.org/bpf/20240429121323.3818497-1-andriy.shevchenko@linux.intel.com
This commit is contained in:
Andy Shevchenko 2024-04-29 15:13:22 +03:00 committed by Andrii Nakryiko
parent 397658ddc8
commit cb01621b6d
1 changed files with 8 additions and 6 deletions
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14
kernel/bpf/core.c
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@ -26,6 +26,7 @@
#include <linux/bpf.h>
#include <linux/btf.h>
#include <linux/objtool.h>
#include <linux/overflow.h>
#include <linux/rbtree_latch.h>
#include <linux/kallsyms.h>
#include <linux/rcupdate.h>
@ -2455,13 +2456,14 @@ EXPORT_SYMBOL(bpf_empty_prog_array);
struct bpf_prog_array *bpf_prog_array_alloc(u32 prog_cnt, gfp_t flags)
{
if (prog_cnt)
return kzalloc(sizeof(struct bpf_prog_array) +
sizeof(struct bpf_prog_array_item) *
(prog_cnt + 1),
flags);
struct bpf_prog_array *p;
return &bpf_empty_prog_array.hdr;
if (prog_cnt)
p = kzalloc(struct_size(p, items, prog_cnt + 1), flags);
else
p = &bpf_empty_prog_array.hdr;
return p;
}
void bpf_prog_array_free(struct bpf_prog_array *progs)