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x86: __memcpy_flushcache: fix wrong alignment if size > 2^32
The first "if" condition in __memcpy_flushcache is supposed to align the "dest" variable to 8 bytes and copy data up to this alignment. However, this condition may misbehave if "size" is greater than 4GiB. The statement min_t(unsigned, size, ALIGN(dest, 8) - dest); casts both arguments to unsigned int and selects the smaller one. However, the cast truncates high bits in "size" and it results in misbehavior. For example: suppose that size == 0x100000001, dest == 0x200000002 min_t(unsigned, size, ALIGN(dest, 8) - dest) == min_t(0x1, 0xe) == 0x1; ... dest += 0x1; so we copy just one byte "and" dest remains unaligned. This patch fixes the bug by replacing unsigned with size_t. Signed-off-by: Mikulas Patocka <mpatocka@redhat.com> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -119,7 +119,7 @@ void __memcpy_flushcache(void *_dst, const void *_src, size_t size)
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/* cache copy and flush to align dest */
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if (!IS_ALIGNED(dest, 8)) {
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unsigned len = min_t(unsigned, size, ALIGN(dest, 8) - dest);
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size_t len = min_t(size_t, size, ALIGN(dest, 8) - dest);
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memcpy((void *) dest, (void *) source, len);
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clean_cache_range((void *) dest, len);
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