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bpf, x64: fix memleak when not converging after image
While reviewing x64 JIT code, I noticed that we leak the prior allocated JIT image in the case where proglen != oldproglen during the JIT passes. Prior to the commite0ee9c1215
("x86: bpf_jit: fix two bugs in eBPF JIT compiler") we would just break out of the loop, and using the image as the JITed prog since it could only shrink in size anyway. Aftere0ee9c1215
, we would bail out to out_addrs label where we free addrs and jit_data but not the image coming from bpf_jit_binary_alloc(). Fixes:e0ee9c1215
("x86: bpf_jit: fix two bugs in eBPF JIT compiler") Signed-off-by: Daniel Borkmann <daniel@iogearbox.net> Acked-by: Alexei Starovoitov <ast@kernel.org> Acked-by: David S. Miller <davem@davemloft.net> Signed-off-by: Alexei Starovoitov <ast@kernel.org>
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1 changed files with 2 additions and 2 deletions
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@ -1236,6 +1236,7 @@ struct bpf_prog *bpf_int_jit_compile(struct bpf_prog *prog)
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for (pass = 0; pass < 20 || image; pass++) {
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proglen = do_jit(prog, addrs, image, oldproglen, &ctx);
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if (proglen <= 0) {
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out_image:
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image = NULL;
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if (header)
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bpf_jit_binary_free(header);
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@ -1246,8 +1247,7 @@ struct bpf_prog *bpf_int_jit_compile(struct bpf_prog *prog)
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if (proglen != oldproglen) {
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pr_err("bpf_jit: proglen=%d != oldproglen=%d\n",
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proglen, oldproglen);
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prog = orig_prog;
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goto out_addrs;
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goto out_image;
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}
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break;
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}
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