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kboot: Allocate a really big first segment
Allocate a huge segment for the first kexec_load segments. We limit the lessor of: allocation to the size of the remaining memory segment 45% of available memory 95% of the memory we can allocate This allows us to have really large RAM disks. We likely need to limit this to the amount we actually used, though, since this can be a lot of memory. We have to do this complicated calculation for a few reasons: First, we need 2 copies of the loaded kernel in the memory: The kernel can copy everything to a temporary buffer. Next, malloc (via mmap) is limited to a certain amount due to over commit, so we have to not allocate all we can (only most of what we can). Sponsored by: Netflix Reviewed by: tsoome Differential Revision: https://reviews.freebsd.org/D38314
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@ -322,6 +322,7 @@ get_phys_buffer(vm_offset_t dest, const size_t len, void **buf)
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{
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int i = 0;
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const size_t segsize = 64*1024*1024;
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size_t sz;
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if (nkexec_segments == HOST_KEXEC_SEGMENT_MAX)
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panic("Tried to load too many kexec segments");
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@ -332,10 +333,22 @@ get_phys_buffer(vm_offset_t dest, const size_t len, void **buf)
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goto out;
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}
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loaded_segments[nkexec_segments].buf = host_getmem(segsize);
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loaded_segments[nkexec_segments].bufsz = segsize;
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sz = segsize;
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if (nkexec_segments == 0) {
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/* how much space does this segment have */
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sz = space_avail(dest);
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/* Clip to 45% of available memory (need 2 copies) */
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sz = min(sz, rounddown2(mem_avail * 45 / 100, SEGALIGN));
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/* And only use 95% of what we can allocate */
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sz = min(sz, rounddown2(
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(commit_limit - committed_as) * 95 / 100, SEGALIGN));
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printf("Allocating %zd MB for first segment\n", sz >> 20);
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}
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loaded_segments[nkexec_segments].buf = host_getmem(sz);
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loaded_segments[nkexec_segments].bufsz = sz;
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loaded_segments[nkexec_segments].mem = (void *)rounddown2(dest,SEGALIGN);
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loaded_segments[nkexec_segments].memsz = segsize;
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loaded_segments[nkexec_segments].memsz = sz;
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i = nkexec_segments;
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nkexec_segments++;
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