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1dd24d8216
Two interface types that are assignable don't have to be identical; specifically, if they are defined types, they can be different defined types. If those defined types specify type parameters which are never used, do not infer a type argument based on the instantiation of a matching defined type. Adjusted three existing tests where we inferred type arguments incorrectly. Fixes #60377. Change-Id: I91fb207235424b3cbc42b5fd93eee619e7541cb7 Reviewed-on: https://go-review.googlesource.com/c/go/+/498315 Auto-Submit: Robert Griesemer <gri@google.com> Reviewed-by: Robert Findley <rfindley@google.com> Reviewed-by: Robert Griesemer <gri@google.com> Run-TryBot: Robert Griesemer <gri@google.com> TryBot-Result: Gopher Robot <gobot@golang.org>
19 lines
309 B
Go
19 lines
309 B
Go
// compile
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// Copyright 2022 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package main
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type Value[T any] interface {
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}
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func use[T any](v Value[T]) {
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_, _ = v.(int)
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}
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func main() {
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use[int](Value[int](1))
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}
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