The compiler use to compile f()(g()) as:
t1, t2 := g()
f()(t1, t2)
That violates the Go spec, since when "..., all function calls, ... are
evaluated in lexical left-to-right order"
This PR fixes the bug by compiling f()(g()) as:
t0 := f()
t1, t2 := g()
t0(t1, t2)
to make "f()" to be evaluated before "g()".
Fixes#50672
Change-Id: I6a766f3dfc7347d10f8fa3a151f6a5ea79bcf818
Reviewed-on: https://go-review.googlesource.com/c/go/+/392834
TryBot-Result: Gopher Robot <gobot@golang.org>
Auto-Submit: Cuong Manh Le <cuong.manhle.vn@gmail.com>
Reviewed-by: Keith Randall <khr@google.com>
Reviewed-by: Matthew Dempsky <mdempsky@google.com>
Run-TryBot: Cuong Manh Le <cuong.manhle.vn@gmail.com>
