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Fix typo in exponent representation example

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Change-Id: I7e082bc7a6e193fe783263b2a074ad5d348c85c8
Reviewed-on: https://dart-review.googlesource.com/13980
Reviewed-by: Florian Loitsch <floitsch@google.com>
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Florian Loitsch 2017-10-14 14:31:32 +00:00
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docs/newsletter/20171013.md
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@ -34,7 +34,7 @@ In this section I will focus on Dart's `toString` methods of `double`. There are
- `toStringAsFixed`
- `toStringAsPrecision`
The `double.toString` method is the most commonly used way of converting a double to a string. It uses a mixture of `toStringAsExponential` and `toStringAsFixed` to provide the most visibly appealing output. For large numbers (more than 20 digits) it emits an exponential representation as in `1.3e+21`. The same is true for very small floating-point numbers, strictly smaller than the one represented by `0.000001`. For example `0.000000998` is printed as `0.98e-7`. All other numbers are printed in the "normal" decimal representation: `5.0`, `1.23`, or `0.001`.
The `double.toString` method is the most commonly used way of converting a double to a string. It uses a mixture of `toStringAsExponential` and `toStringAsFixed` to provide the most visibly appealing output. For large numbers (more than 20 digits) it emits an exponential representation as in `1.3e+21`. The same is true for very small floating-point numbers, strictly smaller than the one represented by `0.000001`. For example `0.000000998` is printed as `9.98e-7`. All other numbers are printed in the "normal" decimal representation: `5.0`, `1.23`, or `0.001`.
The other methods just force a specific representation. I encourage readers to experiment with them, but I won't explain them in this section.