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New test, checking allowed usages of void
typed expressions
Change-Id: I9a3096bb3fb3deca178688029657cd71f8aedf7d Reviewed-on: https://dart-review.googlesource.com/30840 Reviewed-by: Lasse R.H. Nielsen <lrn@google.com> Commit-Queue: Erik Ernst <eernst@google.com>
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tests/language_2/generalized_void_usage_test.dart
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tests/language_2/generalized_void_usage_test.dart
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// Copyright (c) 2017, the Dart project authors. Please see the AUTHORS file
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// for details. All rights reserved. Use of this source code is governed by a
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// BSD-style license that can be found in the LICENSE file.
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// Dart test for static checks on situations where expressions of type void
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// can be used. The point is simply that there are no compile-time errors.
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// We need expressions of type `void`; `void x` would do, but using
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// `void get x` will work with tools that do not yet handle `void x`.
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void get x => null;
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void use(dynamic x) {}
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main() {
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// In an expressionStatement `e;`, e may have type void.
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x;
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// In the initialization and increment expressions of a for-loop,
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// `for (e1; e2; e3) {..}`, `e1` and `e3` may have type void.
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for (x;; x) {
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break;
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}
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// In a typeCast `e as T`, `e` may have type void.
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var y = x as Object;
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// In a parenthesized expression `(e)`, `e` may have type void.
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(x);
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// In a return statement `return e;`, when the return type of the
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// innermost enclosing function is the type void, e may have type void.
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void f() => x;
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void g() {
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return x;
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}
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}
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