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TBR: Typos fixed

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Change-Id: I8c48953541a36f516d7a9bd27de85193bf189930
Reviewed-on: https://dart-review.googlesource.com/57825
Reviewed-by: Erik Ernst <eernst@google.com>
This commit is contained in:
Erik Ernst 2018-06-01 15:15:32 +00:00
parent 545ad130a2
commit 6f68bec1bc
1 changed files with 3 additions and 3 deletions
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6
docs/language/dartLangSpec.tex
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@ -3293,7 +3293,7 @@ A {\em numeric literal} is either a decimal or hexadecimal numeral representing
{`\escapegrammar .}' DIGIT+ EXPONENT?
.
{\bf EXPONENT:}(`e' $|$ `E') (`+' $|$ `-'')? DIGIT+
{\bf EXPONENT:}(`e' $|$ `E') (`+' $|$ `-')? DIGIT+
.
{\bf HEX\_NUMBER:}`0x' HEX\_DIGIT+;
@ -3330,8 +3330,8 @@ A hexadecimal integer literal with numeric value $i$ is a compile-time
error if $i \ge{} 2^{64}$, unless it is prefixed by a unary minus operator,
in which case it is a compile-time error if $i \gt{} 2^{63}$.
If the \code{int} class is implemented as signed 64-bit two's complement integers,
$i \ge{} 2^63$, and the literal is not prefixed by a unary minus operator, then
the literal evaluates to an instance of the \code{int} class representing the integer value $i - 2^64$.
$i \ge{} 2^{63}$, and the literal is not prefixed by a unary minus operator, then
the literal evaluates to an instance of the \code{int} class representing the integer value $i - 2^{64}$.
Otherwise the literal evaluates to an instance of the \code{int} class representing
the integer value $i$,
and it is a compile-time error if the integer $i$ cannot be represented exactly