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===============
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Programming FAQ
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===============
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.. only:: html
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.. contents::
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General Questions
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=================
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Is there a source code level debugger with breakpoints, single-stepping, etc.?
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------------------------------------------------------------------------------
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Yes.
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Several debuggers for Python are described below, and the built-in function
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:func:`breakpoint` allows you to drop into any of them.
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The pdb module is a simple but adequate console-mode debugger for Python. It is
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part of the standard Python library, and is :mod:`documented in the Library
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Reference Manual <pdb>`. You can also write your own debugger by using the code
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for pdb as an example.
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The IDLE interactive development environment, which is part of the standard
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Python distribution (normally available as Tools/scripts/idle), includes a
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graphical debugger.
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PythonWin is a Python IDE that includes a GUI debugger based on pdb. The
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PythonWin debugger colors breakpoints and has quite a few cool features such as
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debugging non-PythonWin programs. PythonWin is available as part of
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`pywin32 <https://github.com/mhammond/pywin32>`_ project and
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as a part of the
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`ActivePython <https://www.activestate.com/products/python/>`_ distribution.
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`Eric <http://eric-ide.python-projects.org/>`_ is an IDE built on PyQt
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and the Scintilla editing component.
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`trepan3k <https://github.com/rocky/python3-trepan/>`_ is a gdb-like debugger.
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`Visual Studio Code <https://code.visualstudio.com/>`_ is an IDE with debugging
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tools that integrates with version-control software.
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There are a number of commercial Python IDEs that include graphical debuggers.
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They include:
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* `Wing IDE <https://wingware.com/>`_
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* `Komodo IDE <https://www.activestate.com/products/komodo-ide/>`_
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* `PyCharm <https://www.jetbrains.com/pycharm/>`_
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Are there tools to help find bugs or perform static analysis?
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-------------------------------------------------------------
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Yes.
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`Pylint <https://www.pylint.org/>`_ and
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`Pyflakes <https://github.com/PyCQA/pyflakes>`_ do basic checking that will
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help you catch bugs sooner.
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Static type checkers such as `Mypy <http://mypy-lang.org/>`_,
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`Pyre <https://pyre-check.org/>`_, and
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`Pytype <https://github.com/google/pytype>`_ can check type hints in Python
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source code.
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.. _faq-create-standalone-binary:
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How can I create a stand-alone binary from a Python script?
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-----------------------------------------------------------
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You don't need the ability to compile Python to C code if all you want is a
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stand-alone program that users can download and run without having to install
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the Python distribution first. There are a number of tools that determine the
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set of modules required by a program and bind these modules together with a
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Python binary to produce a single executable.
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One is to use the freeze tool, which is included in the Python source tree as
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``Tools/freeze``. It converts Python byte code to C arrays; a C compiler you can
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embed all your modules into a new program, which is then linked with the
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standard Python modules.
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It works by scanning your source recursively for import statements (in both
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forms) and looking for the modules in the standard Python path as well as in the
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source directory (for built-in modules). It then turns the bytecode for modules
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written in Python into C code (array initializers that can be turned into code
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objects using the marshal module) and creates a custom-made config file that
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only contains those built-in modules which are actually used in the program. It
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then compiles the generated C code and links it with the rest of the Python
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interpreter to form a self-contained binary which acts exactly like your script.
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The following packages can help with the creation of console and GUI
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executables:
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* `Nuitka <https://nuitka.net/>`_ (Cross-platform)
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* `PyInstaller <http://www.pyinstaller.org/>`_ (Cross-platform)
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* `PyOxidizer <https://pyoxidizer.readthedocs.io/en/stable/>`_ (Cross-platform)
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* `cx_Freeze <https://marcelotduarte.github.io/cx_Freeze/>`_ (Cross-platform)
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* `py2app <https://github.com/ronaldoussoren/py2app>`_ (macOS only)
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* `py2exe <http://www.py2exe.org/>`_ (Windows only)
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Are there coding standards or a style guide for Python programs?
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----------------------------------------------------------------
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Yes. The coding style required for standard library modules is documented as
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:pep:`8`.
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Core Language
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=============
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Why am I getting an UnboundLocalError when the variable has a value?
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--------------------------------------------------------------------
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It can be a surprise to get the UnboundLocalError in previously working
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code when it is modified by adding an assignment statement somewhere in
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the body of a function.
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This code:
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>>> x = 10
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>>> def bar():
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... print(x)
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>>> bar()
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10
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works, but this code:
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>>> x = 10
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>>> def foo():
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... print(x)
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... x += 1
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results in an UnboundLocalError:
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>>> foo()
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Traceback (most recent call last):
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...
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UnboundLocalError: local variable 'x' referenced before assignment
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This is because when you make an assignment to a variable in a scope, that
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variable becomes local to that scope and shadows any similarly named variable
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in the outer scope. Since the last statement in foo assigns a new value to
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``x``, the compiler recognizes it as a local variable. Consequently when the
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earlier ``print(x)`` attempts to print the uninitialized local variable and
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an error results.
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In the example above you can access the outer scope variable by declaring it
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global:
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>>> x = 10
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>>> def foobar():
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... global x
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... print(x)
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... x += 1
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>>> foobar()
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10
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This explicit declaration is required in order to remind you that (unlike the
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superficially analogous situation with class and instance variables) you are
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actually modifying the value of the variable in the outer scope:
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>>> print(x)
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11
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You can do a similar thing in a nested scope using the :keyword:`nonlocal`
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keyword:
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>>> def foo():
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... x = 10
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... def bar():
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... nonlocal x
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... print(x)
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... x += 1
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... bar()
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... print(x)
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>>> foo()
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10
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11
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What are the rules for local and global variables in Python?
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------------------------------------------------------------
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In Python, variables that are only referenced inside a function are implicitly
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global. If a variable is assigned a value anywhere within the function's body,
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it's assumed to be a local unless explicitly declared as global.
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Though a bit surprising at first, a moment's consideration explains this. On
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one hand, requiring :keyword:`global` for assigned variables provides a bar
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against unintended side-effects. On the other hand, if ``global`` was required
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for all global references, you'd be using ``global`` all the time. You'd have
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to declare as global every reference to a built-in function or to a component of
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an imported module. This clutter would defeat the usefulness of the ``global``
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declaration for identifying side-effects.
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Why do lambdas defined in a loop with different values all return the same result?
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----------------------------------------------------------------------------------
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Assume you use a for loop to define a few different lambdas (or even plain
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functions), e.g.::
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>>> squares = []
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>>> for x in range(5):
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... squares.append(lambda: x**2)
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This gives you a list that contains 5 lambdas that calculate ``x**2``. You
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might expect that, when called, they would return, respectively, ``0``, ``1``,
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``4``, ``9``, and ``16``. However, when you actually try you will see that
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they all return ``16``::
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>>> squares[2]()
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16
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>>> squares[4]()
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16
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This happens because ``x`` is not local to the lambdas, but is defined in
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the outer scope, and it is accessed when the lambda is called --- not when it
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is defined. At the end of the loop, the value of ``x`` is ``4``, so all the
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functions now return ``4**2``, i.e. ``16``. You can also verify this by
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changing the value of ``x`` and see how the results of the lambdas change::
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>>> x = 8
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>>> squares[2]()
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64
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In order to avoid this, you need to save the values in variables local to the
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lambdas, so that they don't rely on the value of the global ``x``::
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>>> squares = []
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>>> for x in range(5):
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... squares.append(lambda n=x: n**2)
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Here, ``n=x`` creates a new variable ``n`` local to the lambda and computed
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when the lambda is defined so that it has the same value that ``x`` had at
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that point in the loop. This means that the value of ``n`` will be ``0``
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in the first lambda, ``1`` in the second, ``2`` in the third, and so on.
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Therefore each lambda will now return the correct result::
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>>> squares[2]()
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4
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>>> squares[4]()
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16
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Note that this behaviour is not peculiar to lambdas, but applies to regular
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functions too.
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How do I share global variables across modules?
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------------------------------------------------
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The canonical way to share information across modules within a single program is
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to create a special module (often called config or cfg). Just import the config
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module in all modules of your application; the module then becomes available as
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a global name. Because there is only one instance of each module, any changes
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made to the module object get reflected everywhere. For example:
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config.py::
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x = 0 # Default value of the 'x' configuration setting
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mod.py::
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import config
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config.x = 1
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main.py::
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import config
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import mod
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print(config.x)
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Note that using a module is also the basis for implementing the Singleton design
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pattern, for the same reason.
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What are the "best practices" for using import in a module?
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-----------------------------------------------------------
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In general, don't use ``from modulename import *``. Doing so clutters the
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importer's namespace, and makes it much harder for linters to detect undefined
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names.
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Import modules at the top of a file. Doing so makes it clear what other modules
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your code requires and avoids questions of whether the module name is in scope.
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Using one import per line makes it easy to add and delete module imports, but
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using multiple imports per line uses less screen space.
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It's good practice if you import modules in the following order:
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1. standard library modules -- e.g. ``sys``, ``os``, ``getopt``, ``re``
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2. third-party library modules (anything installed in Python's site-packages
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directory) -- e.g. mx.DateTime, ZODB, PIL.Image, etc.
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3. locally-developed modules
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It is sometimes necessary to move imports to a function or class to avoid
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problems with circular imports. Gordon McMillan says:
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Circular imports are fine where both modules use the "import <module>" form
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of import. They fail when the 2nd module wants to grab a name out of the
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first ("from module import name") and the import is at the top level. That's
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because names in the 1st are not yet available, because the first module is
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busy importing the 2nd.
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In this case, if the second module is only used in one function, then the import
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can easily be moved into that function. By the time the import is called, the
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first module will have finished initializing, and the second module can do its
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import.
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It may also be necessary to move imports out of the top level of code if some of
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the modules are platform-specific. In that case, it may not even be possible to
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import all of the modules at the top of the file. In this case, importing the
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correct modules in the corresponding platform-specific code is a good option.
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Only move imports into a local scope, such as inside a function definition, if
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it's necessary to solve a problem such as avoiding a circular import or are
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trying to reduce the initialization time of a module. This technique is
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especially helpful if many of the imports are unnecessary depending on how the
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program executes. You may also want to move imports into a function if the
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modules are only ever used in that function. Note that loading a module the
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first time may be expensive because of the one time initialization of the
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module, but loading a module multiple times is virtually free, costing only a
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couple of dictionary lookups. Even if the module name has gone out of scope,
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the module is probably available in :data:`sys.modules`.
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Why are default values shared between objects?
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----------------------------------------------
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This type of bug commonly bites neophyte programmers. Consider this function::
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def foo(mydict={}): # Danger: shared reference to one dict for all calls
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... compute something ...
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mydict[key] = value
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return mydict
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The first time you call this function, ``mydict`` contains a single item. The
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second time, ``mydict`` contains two items because when ``foo()`` begins
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executing, ``mydict`` starts out with an item already in it.
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It is often expected that a function call creates new objects for default
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values. This is not what happens. Default values are created exactly once, when
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the function is defined. If that object is changed, like the dictionary in this
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example, subsequent calls to the function will refer to this changed object.
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By definition, immutable objects such as numbers, strings, tuples, and ``None``,
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are safe from change. Changes to mutable objects such as dictionaries, lists,
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and class instances can lead to confusion.
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Because of this feature, it is good programming practice to not use mutable
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objects as default values. Instead, use ``None`` as the default value and
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inside the function, check if the parameter is ``None`` and create a new
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list/dictionary/whatever if it is. For example, don't write::
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def foo(mydict={}):
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...
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but::
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def foo(mydict=None):
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if mydict is None:
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mydict = {} # create a new dict for local namespace
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This feature can be useful. When you have a function that's time-consuming to
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compute, a common technique is to cache the parameters and the resulting value
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of each call to the function, and return the cached value if the same value is
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requested again. This is called "memoizing", and can be implemented like this::
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# Callers can only provide two parameters and optionally pass _cache by keyword
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def expensive(arg1, arg2, *, _cache={}):
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if (arg1, arg2) in _cache:
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return _cache[(arg1, arg2)]
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# Calculate the value
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result = ... expensive computation ...
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_cache[(arg1, arg2)] = result # Store result in the cache
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return result
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You could use a global variable containing a dictionary instead of the default
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value; it's a matter of taste.
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How can I pass optional or keyword parameters from one function to another?
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---------------------------------------------------------------------------
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Collect the arguments using the ``*`` and ``**`` specifiers in the function's
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parameter list; this gives you the positional arguments as a tuple and the
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keyword arguments as a dictionary. You can then pass these arguments when
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calling another function by using ``*`` and ``**``::
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def f(x, *args, **kwargs):
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...
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kwargs['width'] = '14.3c'
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...
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g(x, *args, **kwargs)
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.. index::
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single: argument; difference from parameter
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single: parameter; difference from argument
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.. _faq-argument-vs-parameter:
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What is the difference between arguments and parameters?
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--------------------------------------------------------
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:term:`Parameters <parameter>` are defined by the names that appear in a
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function definition, whereas :term:`arguments <argument>` are the values
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actually passed to a function when calling it. Parameters define what types of
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arguments a function can accept. For example, given the function definition::
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def func(foo, bar=None, **kwargs):
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pass
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*foo*, *bar* and *kwargs* are parameters of ``func``. However, when calling
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``func``, for example::
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func(42, bar=314, extra=somevar)
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the values ``42``, ``314``, and ``somevar`` are arguments.
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Why did changing list 'y' also change list 'x'?
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------------------------------------------------
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If you wrote code like::
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>>> x = []
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>>> y = x
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>>> y.append(10)
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>>> y
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[10]
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>>> x
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[10]
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you might be wondering why appending an element to ``y`` changed ``x`` too.
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There are two factors that produce this result:
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1) Variables are simply names that refer to objects. Doing ``y = x`` doesn't
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create a copy of the list -- it creates a new variable ``y`` that refers to
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the same object ``x`` refers to. This means that there is only one object
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(the list), and both ``x`` and ``y`` refer to it.
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2) Lists are :term:`mutable`, which means that you can change their content.
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After the call to :meth:`~list.append`, the content of the mutable object has
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changed from ``[]`` to ``[10]``. Since both the variables refer to the same
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object, using either name accesses the modified value ``[10]``.
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If we instead assign an immutable object to ``x``::
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>>> x = 5 # ints are immutable
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>>> y = x
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>>> x = x + 1 # 5 can't be mutated, we are creating a new object here
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>>> x
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6
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>>> y
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5
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we can see that in this case ``x`` and ``y`` are not equal anymore. This is
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because integers are :term:`immutable`, and when we do ``x = x + 1`` we are not
|
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mutating the int ``5`` by incrementing its value; instead, we are creating a
|
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new object (the int ``6``) and assigning it to ``x`` (that is, changing which
|
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object ``x`` refers to). After this assignment we have two objects (the ints
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``6`` and ``5``) and two variables that refer to them (``x`` now refers to
|
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``6`` but ``y`` still refers to ``5``).
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Some operations (for example ``y.append(10)`` and ``y.sort()``) mutate the
|
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object, whereas superficially similar operations (for example ``y = y + [10]``
|
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and ``sorted(y)``) create a new object. In general in Python (and in all cases
|
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in the standard library) a method that mutates an object will return ``None``
|
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to help avoid getting the two types of operations confused. So if you
|
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mistakenly write ``y.sort()`` thinking it will give you a sorted copy of ``y``,
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you'll instead end up with ``None``, which will likely cause your program to
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generate an easily diagnosed error.
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However, there is one class of operations where the same operation sometimes
|
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has different behaviors with different types: the augmented assignment
|
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operators. For example, ``+=`` mutates lists but not tuples or ints (``a_list
|
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+= [1, 2, 3]`` is equivalent to ``a_list.extend([1, 2, 3])`` and mutates
|
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``a_list``, whereas ``some_tuple += (1, 2, 3)`` and ``some_int += 1`` create
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new objects).
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In other words:
|
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* If we have a mutable object (:class:`list`, :class:`dict`, :class:`set`,
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etc.), we can use some specific operations to mutate it and all the variables
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that refer to it will see the change.
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* If we have an immutable object (:class:`str`, :class:`int`, :class:`tuple`,
|
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etc.), all the variables that refer to it will always see the same value,
|
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but operations that transform that value into a new value always return a new
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object.
|
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If you want to know if two variables refer to the same object or not, you can
|
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use the :keyword:`is` operator, or the built-in function :func:`id`.
|
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|
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How do I write a function with output parameters (call by reference)?
|
|
---------------------------------------------------------------------
|
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Remember that arguments are passed by assignment in Python. Since assignment
|
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just creates references to objects, there's no alias between an argument name in
|
|
the caller and callee, and so no call-by-reference per se. You can achieve the
|
|
desired effect in a number of ways.
|
|
|
|
1) By returning a tuple of the results::
|
|
|
|
>>> def func1(a, b):
|
|
... a = 'new-value' # a and b are local names
|
|
... b = b + 1 # assigned to new objects
|
|
... return a, b # return new values
|
|
...
|
|
>>> x, y = 'old-value', 99
|
|
>>> func1(x, y)
|
|
('new-value', 100)
|
|
|
|
This is almost always the clearest solution.
|
|
|
|
2) By using global variables. This isn't thread-safe, and is not recommended.
|
|
|
|
3) By passing a mutable (changeable in-place) object::
|
|
|
|
>>> def func2(a):
|
|
... a[0] = 'new-value' # 'a' references a mutable list
|
|
... a[1] = a[1] + 1 # changes a shared object
|
|
...
|
|
>>> args = ['old-value', 99]
|
|
>>> func2(args)
|
|
>>> args
|
|
['new-value', 100]
|
|
|
|
4) By passing in a dictionary that gets mutated::
|
|
|
|
>>> def func3(args):
|
|
... args['a'] = 'new-value' # args is a mutable dictionary
|
|
... args['b'] = args['b'] + 1 # change it in-place
|
|
...
|
|
>>> args = {'a': 'old-value', 'b': 99}
|
|
>>> func3(args)
|
|
>>> args
|
|
{'a': 'new-value', 'b': 100}
|
|
|
|
5) Or bundle up values in a class instance::
|
|
|
|
>>> class Namespace:
|
|
... def __init__(self, /, **args):
|
|
... for key, value in args.items():
|
|
... setattr(self, key, value)
|
|
...
|
|
>>> def func4(args):
|
|
... args.a = 'new-value' # args is a mutable Namespace
|
|
... args.b = args.b + 1 # change object in-place
|
|
...
|
|
>>> args = Namespace(a='old-value', b=99)
|
|
>>> func4(args)
|
|
>>> vars(args)
|
|
{'a': 'new-value', 'b': 100}
|
|
|
|
|
|
There's almost never a good reason to get this complicated.
|
|
|
|
Your best choice is to return a tuple containing the multiple results.
|
|
|
|
|
|
How do you make a higher order function in Python?
|
|
--------------------------------------------------
|
|
|
|
You have two choices: you can use nested scopes or you can use callable objects.
|
|
For example, suppose you wanted to define ``linear(a,b)`` which returns a
|
|
function ``f(x)`` that computes the value ``a*x+b``. Using nested scopes::
|
|
|
|
def linear(a, b):
|
|
def result(x):
|
|
return a * x + b
|
|
return result
|
|
|
|
Or using a callable object::
|
|
|
|
class linear:
|
|
|
|
def __init__(self, a, b):
|
|
self.a, self.b = a, b
|
|
|
|
def __call__(self, x):
|
|
return self.a * x + self.b
|
|
|
|
In both cases, ::
|
|
|
|
taxes = linear(0.3, 2)
|
|
|
|
gives a callable object where ``taxes(10e6) == 0.3 * 10e6 + 2``.
|
|
|
|
The callable object approach has the disadvantage that it is a bit slower and
|
|
results in slightly longer code. However, note that a collection of callables
|
|
can share their signature via inheritance::
|
|
|
|
class exponential(linear):
|
|
# __init__ inherited
|
|
def __call__(self, x):
|
|
return self.a * (x ** self.b)
|
|
|
|
Object can encapsulate state for several methods::
|
|
|
|
class counter:
|
|
|
|
value = 0
|
|
|
|
def set(self, x):
|
|
self.value = x
|
|
|
|
def up(self):
|
|
self.value = self.value + 1
|
|
|
|
def down(self):
|
|
self.value = self.value - 1
|
|
|
|
count = counter()
|
|
inc, dec, reset = count.up, count.down, count.set
|
|
|
|
Here ``inc()``, ``dec()`` and ``reset()`` act like functions which share the
|
|
same counting variable.
|
|
|
|
|
|
How do I copy an object in Python?
|
|
----------------------------------
|
|
|
|
In general, try :func:`copy.copy` or :func:`copy.deepcopy` for the general case.
|
|
Not all objects can be copied, but most can.
|
|
|
|
Some objects can be copied more easily. Dictionaries have a :meth:`~dict.copy`
|
|
method::
|
|
|
|
newdict = olddict.copy()
|
|
|
|
Sequences can be copied by slicing::
|
|
|
|
new_l = l[:]
|
|
|
|
|
|
How can I find the methods or attributes of an object?
|
|
------------------------------------------------------
|
|
|
|
For an instance x of a user-defined class, ``dir(x)`` returns an alphabetized
|
|
list of the names containing the instance attributes and methods and attributes
|
|
defined by its class.
|
|
|
|
|
|
How can my code discover the name of an object?
|
|
-----------------------------------------------
|
|
|
|
Generally speaking, it can't, because objects don't really have names.
|
|
Essentially, assignment always binds a name to a value; the same is true of
|
|
``def`` and ``class`` statements, but in that case the value is a
|
|
callable. Consider the following code::
|
|
|
|
>>> class A:
|
|
... pass
|
|
...
|
|
>>> B = A
|
|
>>> a = B()
|
|
>>> b = a
|
|
>>> print(b)
|
|
<__main__.A object at 0x16D07CC>
|
|
>>> print(a)
|
|
<__main__.A object at 0x16D07CC>
|
|
|
|
Arguably the class has a name: even though it is bound to two names and invoked
|
|
through the name B the created instance is still reported as an instance of
|
|
class A. However, it is impossible to say whether the instance's name is a or
|
|
b, since both names are bound to the same value.
|
|
|
|
Generally speaking it should not be necessary for your code to "know the names"
|
|
of particular values. Unless you are deliberately writing introspective
|
|
programs, this is usually an indication that a change of approach might be
|
|
beneficial.
|
|
|
|
In comp.lang.python, Fredrik Lundh once gave an excellent analogy in answer to
|
|
this question:
|
|
|
|
The same way as you get the name of that cat you found on your porch: the cat
|
|
(object) itself cannot tell you its name, and it doesn't really care -- so
|
|
the only way to find out what it's called is to ask all your neighbours
|
|
(namespaces) if it's their cat (object)...
|
|
|
|
....and don't be surprised if you'll find that it's known by many names, or
|
|
no name at all!
|
|
|
|
|
|
What's up with the comma operator's precedence?
|
|
-----------------------------------------------
|
|
|
|
Comma is not an operator in Python. Consider this session::
|
|
|
|
>>> "a" in "b", "a"
|
|
(False, 'a')
|
|
|
|
Since the comma is not an operator, but a separator between expressions the
|
|
above is evaluated as if you had entered::
|
|
|
|
("a" in "b"), "a"
|
|
|
|
not::
|
|
|
|
"a" in ("b", "a")
|
|
|
|
The same is true of the various assignment operators (``=``, ``+=`` etc). They
|
|
are not truly operators but syntactic delimiters in assignment statements.
|
|
|
|
|
|
Is there an equivalent of C's "?:" ternary operator?
|
|
----------------------------------------------------
|
|
|
|
Yes, there is. The syntax is as follows::
|
|
|
|
[on_true] if [expression] else [on_false]
|
|
|
|
x, y = 50, 25
|
|
small = x if x < y else y
|
|
|
|
Before this syntax was introduced in Python 2.5, a common idiom was to use
|
|
logical operators::
|
|
|
|
[expression] and [on_true] or [on_false]
|
|
|
|
However, this idiom is unsafe, as it can give wrong results when *on_true*
|
|
has a false boolean value. Therefore, it is always better to use
|
|
the ``... if ... else ...`` form.
|
|
|
|
|
|
Is it possible to write obfuscated one-liners in Python?
|
|
--------------------------------------------------------
|
|
|
|
Yes. Usually this is done by nesting :keyword:`lambda` within
|
|
:keyword:`!lambda`. See the following three examples, due to Ulf Bartelt::
|
|
|
|
from functools import reduce
|
|
|
|
# Primes < 1000
|
|
print(list(filter(None,map(lambda y:y*reduce(lambda x,y:x*y!=0,
|
|
map(lambda x,y=y:y%x,range(2,int(pow(y,0.5)+1))),1),range(2,1000)))))
|
|
|
|
# First 10 Fibonacci numbers
|
|
print(list(map(lambda x,f=lambda x,f:(f(x-1,f)+f(x-2,f)) if x>1 else 1:
|
|
f(x,f), range(10))))
|
|
|
|
# Mandelbrot set
|
|
print((lambda Ru,Ro,Iu,Io,IM,Sx,Sy:reduce(lambda x,y:x+y,map(lambda y,
|
|
Iu=Iu,Io=Io,Ru=Ru,Ro=Ro,Sy=Sy,L=lambda yc,Iu=Iu,Io=Io,Ru=Ru,Ro=Ro,i=IM,
|
|
Sx=Sx,Sy=Sy:reduce(lambda x,y:x+y,map(lambda x,xc=Ru,yc=yc,Ru=Ru,Ro=Ro,
|
|
i=i,Sx=Sx,F=lambda xc,yc,x,y,k,f=lambda xc,yc,x,y,k,f:(k<=0)or (x*x+y*y
|
|
>=4.0) or 1+f(xc,yc,x*x-y*y+xc,2.0*x*y+yc,k-1,f):f(xc,yc,x,y,k,f):chr(
|
|
64+F(Ru+x*(Ro-Ru)/Sx,yc,0,0,i)),range(Sx))):L(Iu+y*(Io-Iu)/Sy),range(Sy
|
|
))))(-2.1, 0.7, -1.2, 1.2, 30, 80, 24))
|
|
# \___ ___/ \___ ___/ | | |__ lines on screen
|
|
# V V | |______ columns on screen
|
|
# | | |__________ maximum of "iterations"
|
|
# | |_________________ range on y axis
|
|
# |____________________________ range on x axis
|
|
|
|
Don't try this at home, kids!
|
|
|
|
|
|
.. _faq-positional-only-arguments:
|
|
|
|
What does the slash(/) in the parameter list of a function mean?
|
|
----------------------------------------------------------------
|
|
|
|
A slash in the argument list of a function denotes that the parameters prior to
|
|
it are positional-only. Positional-only parameters are the ones without an
|
|
externally-usable name. Upon calling a function that accepts positional-only
|
|
parameters, arguments are mapped to parameters based solely on their position.
|
|
For example, :func:`divmod` is a function that accepts positional-only
|
|
parameters. Its documentation looks like this::
|
|
|
|
>>> help(divmod)
|
|
Help on built-in function divmod in module builtins:
|
|
|
|
divmod(x, y, /)
|
|
Return the tuple (x//y, x%y). Invariant: div*y + mod == x.
|
|
|
|
The slash at the end of the parameter list means that both parameters are
|
|
positional-only. Thus, calling :func:`divmod` with keyword arguments would lead
|
|
to an error::
|
|
|
|
>>> divmod(x=3, y=4)
|
|
Traceback (most recent call last):
|
|
File "<stdin>", line 1, in <module>
|
|
TypeError: divmod() takes no keyword arguments
|
|
|
|
|
|
Numbers and strings
|
|
===================
|
|
|
|
How do I specify hexadecimal and octal integers?
|
|
------------------------------------------------
|
|
|
|
To specify an octal digit, precede the octal value with a zero, and then a lower
|
|
or uppercase "o". For example, to set the variable "a" to the octal value "10"
|
|
(8 in decimal), type::
|
|
|
|
>>> a = 0o10
|
|
>>> a
|
|
8
|
|
|
|
Hexadecimal is just as easy. Simply precede the hexadecimal number with a zero,
|
|
and then a lower or uppercase "x". Hexadecimal digits can be specified in lower
|
|
or uppercase. For example, in the Python interpreter::
|
|
|
|
>>> a = 0xa5
|
|
>>> a
|
|
165
|
|
>>> b = 0XB2
|
|
>>> b
|
|
178
|
|
|
|
|
|
Why does -22 // 10 return -3?
|
|
-----------------------------
|
|
|
|
It's primarily driven by the desire that ``i % j`` have the same sign as ``j``.
|
|
If you want that, and also want::
|
|
|
|
i == (i // j) * j + (i % j)
|
|
|
|
then integer division has to return the floor. C also requires that identity to
|
|
hold, and then compilers that truncate ``i // j`` need to make ``i % j`` have
|
|
the same sign as ``i``.
|
|
|
|
There are few real use cases for ``i % j`` when ``j`` is negative. When ``j``
|
|
is positive, there are many, and in virtually all of them it's more useful for
|
|
``i % j`` to be ``>= 0``. If the clock says 10 now, what did it say 200 hours
|
|
ago? ``-190 % 12 == 2`` is useful; ``-190 % 12 == -10`` is a bug waiting to
|
|
bite.
|
|
|
|
|
|
How do I get int literal attribute instead of SyntaxError?
|
|
----------------------------------------------------------
|
|
|
|
Trying to lookup an ``int`` literal attribute in the normal manner gives
|
|
a syntax error because the period is seen as a decimal point::
|
|
|
|
>>> 1.__class__
|
|
File "<stdin>", line 1
|
|
1.__class__
|
|
^
|
|
SyntaxError: invalid decimal literal
|
|
|
|
The solution is to separate the literal from the period
|
|
with either a space or parentheses.
|
|
|
|
>>> 1 .__class__
|
|
<class 'int'>
|
|
>>> (1).__class__
|
|
<class 'int'>
|
|
|
|
|
|
How do I convert a string to a number?
|
|
--------------------------------------
|
|
|
|
For integers, use the built-in :func:`int` type constructor, e.g. ``int('144')
|
|
== 144``. Similarly, :func:`float` converts to floating-point,
|
|
e.g. ``float('144') == 144.0``.
|
|
|
|
By default, these interpret the number as decimal, so that ``int('0144') ==
|
|
144`` holds true, and ``int('0x144')`` raises :exc:`ValueError`. ``int(string,
|
|
base)`` takes the base to convert from as a second optional argument, so ``int(
|
|
'0x144', 16) == 324``. If the base is specified as 0, the number is interpreted
|
|
using Python's rules: a leading '0o' indicates octal, and '0x' indicates a hex
|
|
number.
|
|
|
|
Do not use the built-in function :func:`eval` if all you need is to convert
|
|
strings to numbers. :func:`eval` will be significantly slower and it presents a
|
|
security risk: someone could pass you a Python expression that might have
|
|
unwanted side effects. For example, someone could pass
|
|
``__import__('os').system("rm -rf $HOME")`` which would erase your home
|
|
directory.
|
|
|
|
:func:`eval` also has the effect of interpreting numbers as Python expressions,
|
|
so that e.g. ``eval('09')`` gives a syntax error because Python does not allow
|
|
leading '0' in a decimal number (except '0').
|
|
|
|
|
|
How do I convert a number to a string?
|
|
--------------------------------------
|
|
|
|
To convert, e.g., the number 144 to the string '144', use the built-in type
|
|
constructor :func:`str`. If you want a hexadecimal or octal representation, use
|
|
the built-in functions :func:`hex` or :func:`oct`. For fancy formatting, see
|
|
the :ref:`f-strings` and :ref:`formatstrings` sections,
|
|
e.g. ``"{:04d}".format(144)`` yields
|
|
``'0144'`` and ``"{:.3f}".format(1.0/3.0)`` yields ``'0.333'``.
|
|
|
|
|
|
How do I modify a string in place?
|
|
----------------------------------
|
|
|
|
You can't, because strings are immutable. In most situations, you should
|
|
simply construct a new string from the various parts you want to assemble
|
|
it from. However, if you need an object with the ability to modify in-place
|
|
unicode data, try using an :class:`io.StringIO` object or the :mod:`array`
|
|
module::
|
|
|
|
>>> import io
|
|
>>> s = "Hello, world"
|
|
>>> sio = io.StringIO(s)
|
|
>>> sio.getvalue()
|
|
'Hello, world'
|
|
>>> sio.seek(7)
|
|
7
|
|
>>> sio.write("there!")
|
|
6
|
|
>>> sio.getvalue()
|
|
'Hello, there!'
|
|
|
|
>>> import array
|
|
>>> a = array.array('u', s)
|
|
>>> print(a)
|
|
array('u', 'Hello, world')
|
|
>>> a[0] = 'y'
|
|
>>> print(a)
|
|
array('u', 'yello, world')
|
|
>>> a.tounicode()
|
|
'yello, world'
|
|
|
|
|
|
How do I use strings to call functions/methods?
|
|
-----------------------------------------------
|
|
|
|
There are various techniques.
|
|
|
|
* The best is to use a dictionary that maps strings to functions. The primary
|
|
advantage of this technique is that the strings do not need to match the names
|
|
of the functions. This is also the primary technique used to emulate a case
|
|
construct::
|
|
|
|
def a():
|
|
pass
|
|
|
|
def b():
|
|
pass
|
|
|
|
dispatch = {'go': a, 'stop': b} # Note lack of parens for funcs
|
|
|
|
dispatch[get_input()]() # Note trailing parens to call function
|
|
|
|
* Use the built-in function :func:`getattr`::
|
|
|
|
import foo
|
|
getattr(foo, 'bar')()
|
|
|
|
Note that :func:`getattr` works on any object, including classes, class
|
|
instances, modules, and so on.
|
|
|
|
This is used in several places in the standard library, like this::
|
|
|
|
class Foo:
|
|
def do_foo(self):
|
|
...
|
|
|
|
def do_bar(self):
|
|
...
|
|
|
|
f = getattr(foo_instance, 'do_' + opname)
|
|
f()
|
|
|
|
|
|
* Use :func:`locals` to resolve the function name::
|
|
|
|
def myFunc():
|
|
print("hello")
|
|
|
|
fname = "myFunc"
|
|
|
|
f = locals()[fname]
|
|
f()
|
|
|
|
|
|
Is there an equivalent to Perl's chomp() for removing trailing newlines from strings?
|
|
-------------------------------------------------------------------------------------
|
|
|
|
You can use ``S.rstrip("\r\n")`` to remove all occurrences of any line
|
|
terminator from the end of the string ``S`` without removing other trailing
|
|
whitespace. If the string ``S`` represents more than one line, with several
|
|
empty lines at the end, the line terminators for all the blank lines will
|
|
be removed::
|
|
|
|
>>> lines = ("line 1 \r\n"
|
|
... "\r\n"
|
|
... "\r\n")
|
|
>>> lines.rstrip("\n\r")
|
|
'line 1 '
|
|
|
|
Since this is typically only desired when reading text one line at a time, using
|
|
``S.rstrip()`` this way works well.
|
|
|
|
|
|
Is there a scanf() or sscanf() equivalent?
|
|
------------------------------------------
|
|
|
|
Not as such.
|
|
|
|
For simple input parsing, the easiest approach is usually to split the line into
|
|
whitespace-delimited words using the :meth:`~str.split` method of string objects
|
|
and then convert decimal strings to numeric values using :func:`int` or
|
|
:func:`float`. ``split()`` supports an optional "sep" parameter which is useful
|
|
if the line uses something other than whitespace as a separator.
|
|
|
|
For more complicated input parsing, regular expressions are more powerful
|
|
than C's :c:func:`sscanf` and better suited for the task.
|
|
|
|
|
|
What does 'UnicodeDecodeError' or 'UnicodeEncodeError' error mean?
|
|
-------------------------------------------------------------------
|
|
|
|
See the :ref:`unicode-howto`.
|
|
|
|
|
|
Performance
|
|
===========
|
|
|
|
My program is too slow. How do I speed it up?
|
|
---------------------------------------------
|
|
|
|
That's a tough one, in general. First, here are a list of things to
|
|
remember before diving further:
|
|
|
|
* Performance characteristics vary across Python implementations. This FAQ
|
|
focuses on :term:`CPython`.
|
|
* Behaviour can vary across operating systems, especially when talking about
|
|
I/O or multi-threading.
|
|
* You should always find the hot spots in your program *before* attempting to
|
|
optimize any code (see the :mod:`profile` module).
|
|
* Writing benchmark scripts will allow you to iterate quickly when searching
|
|
for improvements (see the :mod:`timeit` module).
|
|
* It is highly recommended to have good code coverage (through unit testing
|
|
or any other technique) before potentially introducing regressions hidden
|
|
in sophisticated optimizations.
|
|
|
|
That being said, there are many tricks to speed up Python code. Here are
|
|
some general principles which go a long way towards reaching acceptable
|
|
performance levels:
|
|
|
|
* Making your algorithms faster (or changing to faster ones) can yield
|
|
much larger benefits than trying to sprinkle micro-optimization tricks
|
|
all over your code.
|
|
|
|
* Use the right data structures. Study documentation for the :ref:`bltin-types`
|
|
and the :mod:`collections` module.
|
|
|
|
* When the standard library provides a primitive for doing something, it is
|
|
likely (although not guaranteed) to be faster than any alternative you
|
|
may come up with. This is doubly true for primitives written in C, such
|
|
as builtins and some extension types. For example, be sure to use
|
|
either the :meth:`list.sort` built-in method or the related :func:`sorted`
|
|
function to do sorting (and see the :ref:`sortinghowto` for examples
|
|
of moderately advanced usage).
|
|
|
|
* Abstractions tend to create indirections and force the interpreter to work
|
|
more. If the levels of indirection outweigh the amount of useful work
|
|
done, your program will be slower. You should avoid excessive abstraction,
|
|
especially under the form of tiny functions or methods (which are also often
|
|
detrimental to readability).
|
|
|
|
If you have reached the limit of what pure Python can allow, there are tools
|
|
to take you further away. For example, `Cython <http://cython.org>`_ can
|
|
compile a slightly modified version of Python code into a C extension, and
|
|
can be used on many different platforms. Cython can take advantage of
|
|
compilation (and optional type annotations) to make your code significantly
|
|
faster than when interpreted. If you are confident in your C programming
|
|
skills, you can also :ref:`write a C extension module <extending-index>`
|
|
yourself.
|
|
|
|
.. seealso::
|
|
The wiki page devoted to `performance tips
|
|
<https://wiki.python.org/moin/PythonSpeed/PerformanceTips>`_.
|
|
|
|
.. _efficient_string_concatenation:
|
|
|
|
What is the most efficient way to concatenate many strings together?
|
|
--------------------------------------------------------------------
|
|
|
|
:class:`str` and :class:`bytes` objects are immutable, therefore concatenating
|
|
many strings together is inefficient as each concatenation creates a new
|
|
object. In the general case, the total runtime cost is quadratic in the
|
|
total string length.
|
|
|
|
To accumulate many :class:`str` objects, the recommended idiom is to place
|
|
them into a list and call :meth:`str.join` at the end::
|
|
|
|
chunks = []
|
|
for s in my_strings:
|
|
chunks.append(s)
|
|
result = ''.join(chunks)
|
|
|
|
(another reasonably efficient idiom is to use :class:`io.StringIO`)
|
|
|
|
To accumulate many :class:`bytes` objects, the recommended idiom is to extend
|
|
a :class:`bytearray` object using in-place concatenation (the ``+=`` operator)::
|
|
|
|
result = bytearray()
|
|
for b in my_bytes_objects:
|
|
result += b
|
|
|
|
|
|
Sequences (Tuples/Lists)
|
|
========================
|
|
|
|
How do I convert between tuples and lists?
|
|
------------------------------------------
|
|
|
|
The type constructor ``tuple(seq)`` converts any sequence (actually, any
|
|
iterable) into a tuple with the same items in the same order.
|
|
|
|
For example, ``tuple([1, 2, 3])`` yields ``(1, 2, 3)`` and ``tuple('abc')``
|
|
yields ``('a', 'b', 'c')``. If the argument is a tuple, it does not make a copy
|
|
but returns the same object, so it is cheap to call :func:`tuple` when you
|
|
aren't sure that an object is already a tuple.
|
|
|
|
The type constructor ``list(seq)`` converts any sequence or iterable into a list
|
|
with the same items in the same order. For example, ``list((1, 2, 3))`` yields
|
|
``[1, 2, 3]`` and ``list('abc')`` yields ``['a', 'b', 'c']``. If the argument
|
|
is a list, it makes a copy just like ``seq[:]`` would.
|
|
|
|
|
|
What's a negative index?
|
|
------------------------
|
|
|
|
Python sequences are indexed with positive numbers and negative numbers. For
|
|
positive numbers 0 is the first index 1 is the second index and so forth. For
|
|
negative indices -1 is the last index and -2 is the penultimate (next to last)
|
|
index and so forth. Think of ``seq[-n]`` as the same as ``seq[len(seq)-n]``.
|
|
|
|
Using negative indices can be very convenient. For example ``S[:-1]`` is all of
|
|
the string except for its last character, which is useful for removing the
|
|
trailing newline from a string.
|
|
|
|
|
|
How do I iterate over a sequence in reverse order?
|
|
--------------------------------------------------
|
|
|
|
Use the :func:`reversed` built-in function::
|
|
|
|
for x in reversed(sequence):
|
|
... # do something with x ...
|
|
|
|
This won't touch your original sequence, but build a new copy with reversed
|
|
order to iterate over.
|
|
|
|
|
|
How do you remove duplicates from a list?
|
|
-----------------------------------------
|
|
|
|
See the Python Cookbook for a long discussion of many ways to do this:
|
|
|
|
https://code.activestate.com/recipes/52560/
|
|
|
|
If you don't mind reordering the list, sort it and then scan from the end of the
|
|
list, deleting duplicates as you go::
|
|
|
|
if mylist:
|
|
mylist.sort()
|
|
last = mylist[-1]
|
|
for i in range(len(mylist)-2, -1, -1):
|
|
if last == mylist[i]:
|
|
del mylist[i]
|
|
else:
|
|
last = mylist[i]
|
|
|
|
If all elements of the list may be used as set keys (i.e. they are all
|
|
:term:`hashable`) this is often faster ::
|
|
|
|
mylist = list(set(mylist))
|
|
|
|
This converts the list into a set, thereby removing duplicates, and then back
|
|
into a list.
|
|
|
|
|
|
How do you remove multiple items from a list
|
|
--------------------------------------------
|
|
|
|
As with removing duplicates, explicitly iterating in reverse with a
|
|
delete condition is one possibility. However, it is easier and faster
|
|
to use slice replacement with an implicit or explicit forward iteration.
|
|
Here are three variations.::
|
|
|
|
mylist[:] = filter(keep_function, mylist)
|
|
mylist[:] = (x for x in mylist if keep_condition)
|
|
mylist[:] = [x for x in mylist if keep_condition]
|
|
|
|
The list comprehension may be fastest.
|
|
|
|
|
|
How do you make an array in Python?
|
|
-----------------------------------
|
|
|
|
Use a list::
|
|
|
|
["this", 1, "is", "an", "array"]
|
|
|
|
Lists are equivalent to C or Pascal arrays in their time complexity; the primary
|
|
difference is that a Python list can contain objects of many different types.
|
|
|
|
The ``array`` module also provides methods for creating arrays of fixed types
|
|
with compact representations, but they are slower to index than lists. Also
|
|
note that NumPy and other third party packages define array-like structures with
|
|
various characteristics as well.
|
|
|
|
To get Lisp-style linked lists, you can emulate cons cells using tuples::
|
|
|
|
lisp_list = ("like", ("this", ("example", None) ) )
|
|
|
|
If mutability is desired, you could use lists instead of tuples. Here the
|
|
analogue of lisp car is ``lisp_list[0]`` and the analogue of cdr is
|
|
``lisp_list[1]``. Only do this if you're sure you really need to, because it's
|
|
usually a lot slower than using Python lists.
|
|
|
|
|
|
.. _faq-multidimensional-list:
|
|
|
|
How do I create a multidimensional list?
|
|
----------------------------------------
|
|
|
|
You probably tried to make a multidimensional array like this::
|
|
|
|
>>> A = [[None] * 2] * 3
|
|
|
|
This looks correct if you print it:
|
|
|
|
.. testsetup::
|
|
|
|
A = [[None] * 2] * 3
|
|
|
|
.. doctest::
|
|
|
|
>>> A
|
|
[[None, None], [None, None], [None, None]]
|
|
|
|
But when you assign a value, it shows up in multiple places:
|
|
|
|
.. testsetup::
|
|
|
|
A = [[None] * 2] * 3
|
|
|
|
.. doctest::
|
|
|
|
>>> A[0][0] = 5
|
|
>>> A
|
|
[[5, None], [5, None], [5, None]]
|
|
|
|
The reason is that replicating a list with ``*`` doesn't create copies, it only
|
|
creates references to the existing objects. The ``*3`` creates a list
|
|
containing 3 references to the same list of length two. Changes to one row will
|
|
show in all rows, which is almost certainly not what you want.
|
|
|
|
The suggested approach is to create a list of the desired length first and then
|
|
fill in each element with a newly created list::
|
|
|
|
A = [None] * 3
|
|
for i in range(3):
|
|
A[i] = [None] * 2
|
|
|
|
This generates a list containing 3 different lists of length two. You can also
|
|
use a list comprehension::
|
|
|
|
w, h = 2, 3
|
|
A = [[None] * w for i in range(h)]
|
|
|
|
Or, you can use an extension that provides a matrix datatype; `NumPy
|
|
<http://www.numpy.org/>`_ is the best known.
|
|
|
|
|
|
How do I apply a method to a sequence of objects?
|
|
-------------------------------------------------
|
|
|
|
Use a list comprehension::
|
|
|
|
result = [obj.method() for obj in mylist]
|
|
|
|
.. _faq-augmented-assignment-tuple-error:
|
|
|
|
Why does a_tuple[i] += ['item'] raise an exception when the addition works?
|
|
---------------------------------------------------------------------------
|
|
|
|
This is because of a combination of the fact that augmented assignment
|
|
operators are *assignment* operators, and the difference between mutable and
|
|
immutable objects in Python.
|
|
|
|
This discussion applies in general when augmented assignment operators are
|
|
applied to elements of a tuple that point to mutable objects, but we'll use
|
|
a ``list`` and ``+=`` as our exemplar.
|
|
|
|
If you wrote::
|
|
|
|
>>> a_tuple = (1, 2)
|
|
>>> a_tuple[0] += 1
|
|
Traceback (most recent call last):
|
|
...
|
|
TypeError: 'tuple' object does not support item assignment
|
|
|
|
The reason for the exception should be immediately clear: ``1`` is added to the
|
|
object ``a_tuple[0]`` points to (``1``), producing the result object, ``2``,
|
|
but when we attempt to assign the result of the computation, ``2``, to element
|
|
``0`` of the tuple, we get an error because we can't change what an element of
|
|
a tuple points to.
|
|
|
|
Under the covers, what this augmented assignment statement is doing is
|
|
approximately this::
|
|
|
|
>>> result = a_tuple[0] + 1
|
|
>>> a_tuple[0] = result
|
|
Traceback (most recent call last):
|
|
...
|
|
TypeError: 'tuple' object does not support item assignment
|
|
|
|
It is the assignment part of the operation that produces the error, since a
|
|
tuple is immutable.
|
|
|
|
When you write something like::
|
|
|
|
>>> a_tuple = (['foo'], 'bar')
|
|
>>> a_tuple[0] += ['item']
|
|
Traceback (most recent call last):
|
|
...
|
|
TypeError: 'tuple' object does not support item assignment
|
|
|
|
The exception is a bit more surprising, and even more surprising is the fact
|
|
that even though there was an error, the append worked::
|
|
|
|
>>> a_tuple[0]
|
|
['foo', 'item']
|
|
|
|
To see why this happens, you need to know that (a) if an object implements an
|
|
``__iadd__`` magic method, it gets called when the ``+=`` augmented assignment
|
|
is executed, and its return value is what gets used in the assignment statement;
|
|
and (b) for lists, ``__iadd__`` is equivalent to calling ``extend`` on the list
|
|
and returning the list. That's why we say that for lists, ``+=`` is a
|
|
"shorthand" for ``list.extend``::
|
|
|
|
>>> a_list = []
|
|
>>> a_list += [1]
|
|
>>> a_list
|
|
[1]
|
|
|
|
This is equivalent to::
|
|
|
|
>>> result = a_list.__iadd__([1])
|
|
>>> a_list = result
|
|
|
|
The object pointed to by a_list has been mutated, and the pointer to the
|
|
mutated object is assigned back to ``a_list``. The end result of the
|
|
assignment is a no-op, since it is a pointer to the same object that ``a_list``
|
|
was previously pointing to, but the assignment still happens.
|
|
|
|
Thus, in our tuple example what is happening is equivalent to::
|
|
|
|
>>> result = a_tuple[0].__iadd__(['item'])
|
|
>>> a_tuple[0] = result
|
|
Traceback (most recent call last):
|
|
...
|
|
TypeError: 'tuple' object does not support item assignment
|
|
|
|
The ``__iadd__`` succeeds, and thus the list is extended, but even though
|
|
``result`` points to the same object that ``a_tuple[0]`` already points to,
|
|
that final assignment still results in an error, because tuples are immutable.
|
|
|
|
|
|
I want to do a complicated sort: can you do a Schwartzian Transform in Python?
|
|
------------------------------------------------------------------------------
|
|
|
|
The technique, attributed to Randal Schwartz of the Perl community, sorts the
|
|
elements of a list by a metric which maps each element to its "sort value". In
|
|
Python, use the ``key`` argument for the :meth:`list.sort` method::
|
|
|
|
Isorted = L[:]
|
|
Isorted.sort(key=lambda s: int(s[10:15]))
|
|
|
|
|
|
How can I sort one list by values from another list?
|
|
----------------------------------------------------
|
|
|
|
Merge them into an iterator of tuples, sort the resulting list, and then pick
|
|
out the element you want. ::
|
|
|
|
>>> list1 = ["what", "I'm", "sorting", "by"]
|
|
>>> list2 = ["something", "else", "to", "sort"]
|
|
>>> pairs = zip(list1, list2)
|
|
>>> pairs = sorted(pairs)
|
|
>>> pairs
|
|
[("I'm", 'else'), ('by', 'sort'), ('sorting', 'to'), ('what', 'something')]
|
|
>>> result = [x[1] for x in pairs]
|
|
>>> result
|
|
['else', 'sort', 'to', 'something']
|
|
|
|
|
|
Objects
|
|
=======
|
|
|
|
What is a class?
|
|
----------------
|
|
|
|
A class is the particular object type created by executing a class statement.
|
|
Class objects are used as templates to create instance objects, which embody
|
|
both the data (attributes) and code (methods) specific to a datatype.
|
|
|
|
A class can be based on one or more other classes, called its base class(es). It
|
|
then inherits the attributes and methods of its base classes. This allows an
|
|
object model to be successively refined by inheritance. You might have a
|
|
generic ``Mailbox`` class that provides basic accessor methods for a mailbox,
|
|
and subclasses such as ``MboxMailbox``, ``MaildirMailbox``, ``OutlookMailbox``
|
|
that handle various specific mailbox formats.
|
|
|
|
|
|
What is a method?
|
|
-----------------
|
|
|
|
A method is a function on some object ``x`` that you normally call as
|
|
``x.name(arguments...)``. Methods are defined as functions inside the class
|
|
definition::
|
|
|
|
class C:
|
|
def meth(self, arg):
|
|
return arg * 2 + self.attribute
|
|
|
|
|
|
What is self?
|
|
-------------
|
|
|
|
Self is merely a conventional name for the first argument of a method. A method
|
|
defined as ``meth(self, a, b, c)`` should be called as ``x.meth(a, b, c)`` for
|
|
some instance ``x`` of the class in which the definition occurs; the called
|
|
method will think it is called as ``meth(x, a, b, c)``.
|
|
|
|
See also :ref:`why-self`.
|
|
|
|
|
|
How do I check if an object is an instance of a given class or of a subclass of it?
|
|
-----------------------------------------------------------------------------------
|
|
|
|
Use the built-in function ``isinstance(obj, cls)``. You can check if an object
|
|
is an instance of any of a number of classes by providing a tuple instead of a
|
|
single class, e.g. ``isinstance(obj, (class1, class2, ...))``, and can also
|
|
check whether an object is one of Python's built-in types, e.g.
|
|
``isinstance(obj, str)`` or ``isinstance(obj, (int, float, complex))``.
|
|
|
|
Note that :func:`isinstance` also checks for virtual inheritance from an
|
|
:term:`abstract base class`. So, the test will return ``True`` for a
|
|
registered class even if hasn't directly or indirectly inherited from it. To
|
|
test for "true inheritance", scan the :term:`MRO` of the class:
|
|
|
|
.. testcode::
|
|
|
|
from collections.abc import Mapping
|
|
|
|
class P:
|
|
pass
|
|
|
|
class C(P):
|
|
pass
|
|
|
|
Mapping.register(P)
|
|
|
|
.. doctest::
|
|
|
|
>>> c = C()
|
|
>>> isinstance(c, C) # direct
|
|
True
|
|
>>> isinstance(c, P) # indirect
|
|
True
|
|
>>> isinstance(c, Mapping) # virtual
|
|
True
|
|
|
|
# Actual inheritance chain
|
|
>>> type(c).__mro__
|
|
(<class 'C'>, <class 'P'>, <class 'object'>)
|
|
|
|
# Test for "true inheritance"
|
|
>>> Mapping in type(c).__mro__
|
|
False
|
|
|
|
Note that most programs do not use :func:`isinstance` on user-defined classes
|
|
very often. If you are developing the classes yourself, a more proper
|
|
object-oriented style is to define methods on the classes that encapsulate a
|
|
particular behaviour, instead of checking the object's class and doing a
|
|
different thing based on what class it is. For example, if you have a function
|
|
that does something::
|
|
|
|
def search(obj):
|
|
if isinstance(obj, Mailbox):
|
|
... # code to search a mailbox
|
|
elif isinstance(obj, Document):
|
|
... # code to search a document
|
|
elif ...
|
|
|
|
A better approach is to define a ``search()`` method on all the classes and just
|
|
call it::
|
|
|
|
class Mailbox:
|
|
def search(self):
|
|
... # code to search a mailbox
|
|
|
|
class Document:
|
|
def search(self):
|
|
... # code to search a document
|
|
|
|
obj.search()
|
|
|
|
|
|
What is delegation?
|
|
-------------------
|
|
|
|
Delegation is an object oriented technique (also called a design pattern).
|
|
Let's say you have an object ``x`` and want to change the behaviour of just one
|
|
of its methods. You can create a new class that provides a new implementation
|
|
of the method you're interested in changing and delegates all other methods to
|
|
the corresponding method of ``x``.
|
|
|
|
Python programmers can easily implement delegation. For example, the following
|
|
class implements a class that behaves like a file but converts all written data
|
|
to uppercase::
|
|
|
|
class UpperOut:
|
|
|
|
def __init__(self, outfile):
|
|
self._outfile = outfile
|
|
|
|
def write(self, s):
|
|
self._outfile.write(s.upper())
|
|
|
|
def __getattr__(self, name):
|
|
return getattr(self._outfile, name)
|
|
|
|
Here the ``UpperOut`` class redefines the ``write()`` method to convert the
|
|
argument string to uppercase before calling the underlying
|
|
``self._outfile.write()`` method. All other methods are delegated to the
|
|
underlying ``self._outfile`` object. The delegation is accomplished via the
|
|
``__getattr__`` method; consult :ref:`the language reference <attribute-access>`
|
|
for more information about controlling attribute access.
|
|
|
|
Note that for more general cases delegation can get trickier. When attributes
|
|
must be set as well as retrieved, the class must define a :meth:`__setattr__`
|
|
method too, and it must do so carefully. The basic implementation of
|
|
:meth:`__setattr__` is roughly equivalent to the following::
|
|
|
|
class X:
|
|
...
|
|
def __setattr__(self, name, value):
|
|
self.__dict__[name] = value
|
|
...
|
|
|
|
Most :meth:`__setattr__` implementations must modify ``self.__dict__`` to store
|
|
local state for self without causing an infinite recursion.
|
|
|
|
|
|
How do I call a method defined in a base class from a derived class that extends it?
|
|
------------------------------------------------------------------------------------
|
|
|
|
Use the built-in :func:`super` function::
|
|
|
|
class Derived(Base):
|
|
def meth(self):
|
|
super().meth() # calls Base.meth
|
|
|
|
In the example, :func:`super` will automatically determine the instance from
|
|
which it was called (the ``self`` value), look up the :term:`method resolution
|
|
order` (MRO) with ``type(self).__mro__``, and return the next in line after
|
|
``Derived`` in the MRO: ``Base``.
|
|
|
|
|
|
How can I organize my code to make it easier to change the base class?
|
|
----------------------------------------------------------------------
|
|
|
|
You could assign the base class to an alias and derive from the alias. Then all
|
|
you have to change is the value assigned to the alias. Incidentally, this trick
|
|
is also handy if you want to decide dynamically (e.g. depending on availability
|
|
of resources) which base class to use. Example::
|
|
|
|
class Base:
|
|
...
|
|
|
|
BaseAlias = Base
|
|
|
|
class Derived(BaseAlias):
|
|
...
|
|
|
|
|
|
How do I create static class data and static class methods?
|
|
-----------------------------------------------------------
|
|
|
|
Both static data and static methods (in the sense of C++ or Java) are supported
|
|
in Python.
|
|
|
|
For static data, simply define a class attribute. To assign a new value to the
|
|
attribute, you have to explicitly use the class name in the assignment::
|
|
|
|
class C:
|
|
count = 0 # number of times C.__init__ called
|
|
|
|
def __init__(self):
|
|
C.count = C.count + 1
|
|
|
|
def getcount(self):
|
|
return C.count # or return self.count
|
|
|
|
``c.count`` also refers to ``C.count`` for any ``c`` such that ``isinstance(c,
|
|
C)`` holds, unless overridden by ``c`` itself or by some class on the base-class
|
|
search path from ``c.__class__`` back to ``C``.
|
|
|
|
Caution: within a method of C, an assignment like ``self.count = 42`` creates a
|
|
new and unrelated instance named "count" in ``self``'s own dict. Rebinding of a
|
|
class-static data name must always specify the class whether inside a method or
|
|
not::
|
|
|
|
C.count = 314
|
|
|
|
Static methods are possible::
|
|
|
|
class C:
|
|
@staticmethod
|
|
def static(arg1, arg2, arg3):
|
|
# No 'self' parameter!
|
|
...
|
|
|
|
However, a far more straightforward way to get the effect of a static method is
|
|
via a simple module-level function::
|
|
|
|
def getcount():
|
|
return C.count
|
|
|
|
If your code is structured so as to define one class (or tightly related class
|
|
hierarchy) per module, this supplies the desired encapsulation.
|
|
|
|
|
|
How can I overload constructors (or methods) in Python?
|
|
-------------------------------------------------------
|
|
|
|
This answer actually applies to all methods, but the question usually comes up
|
|
first in the context of constructors.
|
|
|
|
In C++ you'd write
|
|
|
|
.. code-block:: c
|
|
|
|
class C {
|
|
C() { cout << "No arguments\n"; }
|
|
C(int i) { cout << "Argument is " << i << "\n"; }
|
|
}
|
|
|
|
In Python you have to write a single constructor that catches all cases using
|
|
default arguments. For example::
|
|
|
|
class C:
|
|
def __init__(self, i=None):
|
|
if i is None:
|
|
print("No arguments")
|
|
else:
|
|
print("Argument is", i)
|
|
|
|
This is not entirely equivalent, but close enough in practice.
|
|
|
|
You could also try a variable-length argument list, e.g. ::
|
|
|
|
def __init__(self, *args):
|
|
...
|
|
|
|
The same approach works for all method definitions.
|
|
|
|
|
|
I try to use __spam and I get an error about _SomeClassName__spam.
|
|
------------------------------------------------------------------
|
|
|
|
Variable names with double leading underscores are "mangled" to provide a simple
|
|
but effective way to define class private variables. Any identifier of the form
|
|
``__spam`` (at least two leading underscores, at most one trailing underscore)
|
|
is textually replaced with ``_classname__spam``, where ``classname`` is the
|
|
current class name with any leading underscores stripped.
|
|
|
|
This doesn't guarantee privacy: an outside user can still deliberately access
|
|
the "_classname__spam" attribute, and private values are visible in the object's
|
|
``__dict__``. Many Python programmers never bother to use private variable
|
|
names at all.
|
|
|
|
|
|
My class defines __del__ but it is not called when I delete the object.
|
|
-----------------------------------------------------------------------
|
|
|
|
There are several possible reasons for this.
|
|
|
|
The del statement does not necessarily call :meth:`__del__` -- it simply
|
|
decrements the object's reference count, and if this reaches zero
|
|
:meth:`__del__` is called.
|
|
|
|
If your data structures contain circular links (e.g. a tree where each child has
|
|
a parent reference and each parent has a list of children) the reference counts
|
|
will never go back to zero. Once in a while Python runs an algorithm to detect
|
|
such cycles, but the garbage collector might run some time after the last
|
|
reference to your data structure vanishes, so your :meth:`__del__` method may be
|
|
called at an inconvenient and random time. This is inconvenient if you're trying
|
|
to reproduce a problem. Worse, the order in which object's :meth:`__del__`
|
|
methods are executed is arbitrary. You can run :func:`gc.collect` to force a
|
|
collection, but there *are* pathological cases where objects will never be
|
|
collected.
|
|
|
|
Despite the cycle collector, it's still a good idea to define an explicit
|
|
``close()`` method on objects to be called whenever you're done with them. The
|
|
``close()`` method can then remove attributes that refer to subobjects. Don't
|
|
call :meth:`__del__` directly -- :meth:`__del__` should call ``close()`` and
|
|
``close()`` should make sure that it can be called more than once for the same
|
|
object.
|
|
|
|
Another way to avoid cyclical references is to use the :mod:`weakref` module,
|
|
which allows you to point to objects without incrementing their reference count.
|
|
Tree data structures, for instance, should use weak references for their parent
|
|
and sibling references (if they need them!).
|
|
|
|
.. XXX relevant for Python 3?
|
|
|
|
If the object has ever been a local variable in a function that caught an
|
|
expression in an except clause, chances are that a reference to the object
|
|
still exists in that function's stack frame as contained in the stack trace.
|
|
Normally, calling :func:`sys.exc_clear` will take care of this by clearing
|
|
the last recorded exception.
|
|
|
|
Finally, if your :meth:`__del__` method raises an exception, a warning message
|
|
is printed to :data:`sys.stderr`.
|
|
|
|
|
|
How do I get a list of all instances of a given class?
|
|
------------------------------------------------------
|
|
|
|
Python does not keep track of all instances of a class (or of a built-in type).
|
|
You can program the class's constructor to keep track of all instances by
|
|
keeping a list of weak references to each instance.
|
|
|
|
|
|
Why does the result of ``id()`` appear to be not unique?
|
|
--------------------------------------------------------
|
|
|
|
The :func:`id` builtin returns an integer that is guaranteed to be unique during
|
|
the lifetime of the object. Since in CPython, this is the object's memory
|
|
address, it happens frequently that after an object is deleted from memory, the
|
|
next freshly created object is allocated at the same position in memory. This
|
|
is illustrated by this example:
|
|
|
|
>>> id(1000) # doctest: +SKIP
|
|
13901272
|
|
>>> id(2000) # doctest: +SKIP
|
|
13901272
|
|
|
|
The two ids belong to different integer objects that are created before, and
|
|
deleted immediately after execution of the ``id()`` call. To be sure that
|
|
objects whose id you want to examine are still alive, create another reference
|
|
to the object:
|
|
|
|
>>> a = 1000; b = 2000
|
|
>>> id(a) # doctest: +SKIP
|
|
13901272
|
|
>>> id(b) # doctest: +SKIP
|
|
13891296
|
|
|
|
|
|
When can I rely on identity tests with the *is* operator?
|
|
---------------------------------------------------------
|
|
|
|
The ``is`` operator tests for object identity. The test ``a is b`` is
|
|
equivalent to ``id(a) == id(b)``.
|
|
|
|
The most important property of an identity test is that an object is always
|
|
identical to itself, ``a is a`` always returns ``True``. Identity tests are
|
|
usually faster than equality tests. And unlike equality tests, identity tests
|
|
are guaranteed to return a boolean ``True`` or ``False``.
|
|
|
|
However, identity tests can *only* be substituted for equality tests when
|
|
object identity is assured. Generally, there are three circumstances where
|
|
identity is guaranteed:
|
|
|
|
1) Assignments create new names but do not change object identity. After the
|
|
assignment ``new = old``, it is guaranteed that ``new is old``.
|
|
|
|
2) Putting an object in a container that stores object references does not
|
|
change object identity. After the list assignment ``s[0] = x``, it is
|
|
guaranteed that ``s[0] is x``.
|
|
|
|
3) If an object is a singleton, it means that only one instance of that object
|
|
can exist. After the assignments ``a = None`` and ``b = None``, it is
|
|
guaranteed that ``a is b`` because ``None`` is a singleton.
|
|
|
|
In most other circumstances, identity tests are inadvisable and equality tests
|
|
are preferred. In particular, identity tests should not be used to check
|
|
constants such as :class:`int` and :class:`str` which aren't guaranteed to be
|
|
singletons::
|
|
|
|
>>> a = 1000
|
|
>>> b = 500
|
|
>>> c = b + 500
|
|
>>> a is c
|
|
False
|
|
|
|
>>> a = 'Python'
|
|
>>> b = 'Py'
|
|
>>> c = b + 'thon'
|
|
>>> a is c
|
|
False
|
|
|
|
Likewise, new instances of mutable containers are never identical::
|
|
|
|
>>> a = []
|
|
>>> b = []
|
|
>>> a is b
|
|
False
|
|
|
|
In the standard library code, you will see several common patterns for
|
|
correctly using identity tests:
|
|
|
|
1) As recommended by :pep:`8`, an identity test is the preferred way to check
|
|
for ``None``. This reads like plain English in code and avoids confusion with
|
|
other objects that may have boolean values that evaluate to false.
|
|
|
|
2) Detecting optional arguments can be tricky when ``None`` is a valid input
|
|
value. In those situations, you can create an singleton sentinel object
|
|
guaranteed to be distinct from other objects. For example, here is how
|
|
to implement a method that behaves like :meth:`dict.pop`::
|
|
|
|
_sentinel = object()
|
|
|
|
def pop(self, key, default=_sentinel):
|
|
if key in self:
|
|
value = self[key]
|
|
del self[key]
|
|
return value
|
|
if default is _sentinel:
|
|
raise KeyError(key)
|
|
return default
|
|
|
|
3) Container implementations sometimes need to augment equality tests with
|
|
identity tests. This prevents the code from being confused by objects such as
|
|
``float('NaN')`` that are not equal to themselves.
|
|
|
|
For example, here is the implementation of
|
|
:meth:`collections.abc.Sequence.__contains__`::
|
|
|
|
def __contains__(self, value):
|
|
for v in self:
|
|
if v is value or v == value:
|
|
return True
|
|
return False
|
|
|
|
|
|
How can a subclass control what data is stored in an immutable instance?
|
|
------------------------------------------------------------------------
|
|
|
|
When subclassing an immutable type, override the :meth:`__new__` method
|
|
instead of the :meth:`__init__` method. The latter only runs *after* an
|
|
instance is created, which is too late to alter data in an immutable
|
|
instance.
|
|
|
|
All of these immutable classes have a different signature than their
|
|
parent class:
|
|
|
|
.. testcode::
|
|
|
|
from datetime import date
|
|
|
|
class FirstOfMonthDate(date):
|
|
"Always choose the first day of the month"
|
|
def __new__(cls, year, month, day):
|
|
return super().__new__(cls, year, month, 1)
|
|
|
|
class NamedInt(int):
|
|
"Allow text names for some numbers"
|
|
xlat = {'zero': 0, 'one': 1, 'ten': 10}
|
|
def __new__(cls, value):
|
|
value = cls.xlat.get(value, value)
|
|
return super().__new__(cls, value)
|
|
|
|
class TitleStr(str):
|
|
"Convert str to name suitable for a URL path"
|
|
def __new__(cls, s):
|
|
s = s.lower().replace(' ', '-')
|
|
s = ''.join([c for c in s if c.isalnum() or c == '-'])
|
|
return super().__new__(cls, s)
|
|
|
|
The classes can be used like this:
|
|
|
|
.. doctest::
|
|
|
|
>>> FirstOfMonthDate(2012, 2, 14)
|
|
FirstOfMonthDate(2012, 2, 1)
|
|
>>> NamedInt('ten')
|
|
10
|
|
>>> NamedInt(20)
|
|
20
|
|
>>> TitleStr('Blog: Why Python Rocks')
|
|
'blog-why-python-rocks'
|
|
|
|
|
|
How do I cache method calls?
|
|
----------------------------
|
|
|
|
The two principal tools for caching methods are
|
|
:func:`functools.cached_property` and :func:`functools.lru_cache`. The
|
|
former stores results at the instance level and the latter at the class
|
|
level.
|
|
|
|
The *cached_property* approach only works with methods that do not take
|
|
any arguments. It does not create a reference to the instance. The
|
|
cached method result will be kept only as long as the instance is alive.
|
|
|
|
The advantage is that when an instance is not longer used, the cached
|
|
method result will be released right away. The disadvantage is that if
|
|
instances accumulate, so too will the accumulated method results. They
|
|
can grow without bound.
|
|
|
|
The *lru_cache* approach works with methods that have hashable
|
|
arguments. It creates a reference to the instance unless special
|
|
efforts are made to pass in weak references.
|
|
|
|
The advantage of the least recently used algorithm is that the cache is
|
|
bounded by the specified *maxsize*. The disadvantage is that instances
|
|
are kept alive until they age out of the cache or until the cache is
|
|
cleared.
|
|
|
|
This example shows the various techniques::
|
|
|
|
class Weather:
|
|
"Lookup weather information on a government website"
|
|
|
|
def __init__(self, station_id):
|
|
self._station_id = station_id
|
|
# The _station_id is private and immutable
|
|
|
|
def current_temperature(self):
|
|
"Latest hourly observation"
|
|
# Do not cache this because old results
|
|
# can be out of date.
|
|
|
|
@cached_property
|
|
def location(self):
|
|
"Return the longitude/latitude coordinates of the station"
|
|
# Result only depends on the station_id
|
|
|
|
@lru_cache(maxsize=20)
|
|
def historic_rainfall(self, date, units='mm'):
|
|
"Rainfall on a given date"
|
|
# Depends on the station_id, date, and units.
|
|
|
|
The above example assumes that the *station_id* never changes. If the
|
|
relevant instance attributes are mutable, the *cached_property* approach
|
|
can't be made to work because it cannot detect changes to the
|
|
attributes.
|
|
|
|
The *lru_cache* approach can be made to work, but the class needs to define the
|
|
*__eq__* and *__hash__* methods so the cache can detect relevant attribute
|
|
updates::
|
|
|
|
class Weather:
|
|
"Example with a mutable station identifier"
|
|
|
|
def __init__(self, station_id):
|
|
self.station_id = station_id
|
|
|
|
def change_station(self, station_id):
|
|
self.station_id = station_id
|
|
|
|
def __eq__(self, other):
|
|
return self.station_id == other.station_id
|
|
|
|
def __hash__(self):
|
|
return hash(self.station_id)
|
|
|
|
@lru_cache(maxsize=20)
|
|
def historic_rainfall(self, date, units='cm'):
|
|
'Rainfall on a given date'
|
|
# Depends on the station_id, date, and units.
|
|
|
|
|
|
Modules
|
|
=======
|
|
|
|
How do I create a .pyc file?
|
|
----------------------------
|
|
|
|
When a module is imported for the first time (or when the source file has
|
|
changed since the current compiled file was created) a ``.pyc`` file containing
|
|
the compiled code should be created in a ``__pycache__`` subdirectory of the
|
|
directory containing the ``.py`` file. The ``.pyc`` file will have a
|
|
filename that starts with the same name as the ``.py`` file, and ends with
|
|
``.pyc``, with a middle component that depends on the particular ``python``
|
|
binary that created it. (See :pep:`3147` for details.)
|
|
|
|
One reason that a ``.pyc`` file may not be created is a permissions problem
|
|
with the directory containing the source file, meaning that the ``__pycache__``
|
|
subdirectory cannot be created. This can happen, for example, if you develop as
|
|
one user but run as another, such as if you are testing with a web server.
|
|
|
|
Unless the :envvar:`PYTHONDONTWRITEBYTECODE` environment variable is set,
|
|
creation of a .pyc file is automatic if you're importing a module and Python
|
|
has the ability (permissions, free space, etc...) to create a ``__pycache__``
|
|
subdirectory and write the compiled module to that subdirectory.
|
|
|
|
Running Python on a top level script is not considered an import and no
|
|
``.pyc`` will be created. For example, if you have a top-level module
|
|
``foo.py`` that imports another module ``xyz.py``, when you run ``foo`` (by
|
|
typing ``python foo.py`` as a shell command), a ``.pyc`` will be created for
|
|
``xyz`` because ``xyz`` is imported, but no ``.pyc`` file will be created for
|
|
``foo`` since ``foo.py`` isn't being imported.
|
|
|
|
If you need to create a ``.pyc`` file for ``foo`` -- that is, to create a
|
|
``.pyc`` file for a module that is not imported -- you can, using the
|
|
:mod:`py_compile` and :mod:`compileall` modules.
|
|
|
|
The :mod:`py_compile` module can manually compile any module. One way is to use
|
|
the ``compile()`` function in that module interactively::
|
|
|
|
>>> import py_compile
|
|
>>> py_compile.compile('foo.py') # doctest: +SKIP
|
|
|
|
This will write the ``.pyc`` to a ``__pycache__`` subdirectory in the same
|
|
location as ``foo.py`` (or you can override that with the optional parameter
|
|
``cfile``).
|
|
|
|
You can also automatically compile all files in a directory or directories using
|
|
the :mod:`compileall` module. You can do it from the shell prompt by running
|
|
``compileall.py`` and providing the path of a directory containing Python files
|
|
to compile::
|
|
|
|
python -m compileall .
|
|
|
|
|
|
How do I find the current module name?
|
|
--------------------------------------
|
|
|
|
A module can find out its own module name by looking at the predefined global
|
|
variable ``__name__``. If this has the value ``'__main__'``, the program is
|
|
running as a script. Many modules that are usually used by importing them also
|
|
provide a command-line interface or a self-test, and only execute this code
|
|
after checking ``__name__``::
|
|
|
|
def main():
|
|
print('Running test...')
|
|
...
|
|
|
|
if __name__ == '__main__':
|
|
main()
|
|
|
|
|
|
How can I have modules that mutually import each other?
|
|
-------------------------------------------------------
|
|
|
|
Suppose you have the following modules:
|
|
|
|
:file:`foo.py`::
|
|
|
|
from bar import bar_var
|
|
foo_var = 1
|
|
|
|
:file:`bar.py`::
|
|
|
|
from foo import foo_var
|
|
bar_var = 2
|
|
|
|
The problem is that the interpreter will perform the following steps:
|
|
|
|
* main imports ``foo``
|
|
* Empty globals for ``foo`` are created
|
|
* ``foo`` is compiled and starts executing
|
|
* ``foo`` imports ``bar``
|
|
* Empty globals for ``bar`` are created
|
|
* ``bar`` is compiled and starts executing
|
|
* ``bar`` imports ``foo`` (which is a no-op since there already is a module named ``foo``)
|
|
* The import mechanism tries to read ``foo_var`` from ``foo`` globals, to set ``bar.foo_var = foo.foo_var``
|
|
|
|
The last step fails, because Python isn't done with interpreting ``foo`` yet and
|
|
the global symbol dictionary for ``foo`` is still empty.
|
|
|
|
The same thing happens when you use ``import foo``, and then try to access
|
|
``foo.foo_var`` in global code.
|
|
|
|
There are (at least) three possible workarounds for this problem.
|
|
|
|
Guido van Rossum recommends avoiding all uses of ``from <module> import ...``,
|
|
and placing all code inside functions. Initializations of global variables and
|
|
class variables should use constants or built-in functions only. This means
|
|
everything from an imported module is referenced as ``<module>.<name>``.
|
|
|
|
Jim Roskind suggests performing steps in the following order in each module:
|
|
|
|
* exports (globals, functions, and classes that don't need imported base
|
|
classes)
|
|
* ``import`` statements
|
|
* active code (including globals that are initialized from imported values).
|
|
|
|
van Rossum doesn't like this approach much because the imports appear in a
|
|
strange place, but it does work.
|
|
|
|
Matthias Urlichs recommends restructuring your code so that the recursive import
|
|
is not necessary in the first place.
|
|
|
|
These solutions are not mutually exclusive.
|
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__import__('x.y.z') returns <module 'x'>; how do I get z?
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---------------------------------------------------------
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Consider using the convenience function :func:`~importlib.import_module` from
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:mod:`importlib` instead::
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z = importlib.import_module('x.y.z')
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When I edit an imported module and reimport it, the changes don't show up. Why does this happen?
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-------------------------------------------------------------------------------------------------
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For reasons of efficiency as well as consistency, Python only reads the module
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file on the first time a module is imported. If it didn't, in a program
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consisting of many modules where each one imports the same basic module, the
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basic module would be parsed and re-parsed many times. To force re-reading of a
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changed module, do this::
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import importlib
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import modname
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importlib.reload(modname)
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Warning: this technique is not 100% fool-proof. In particular, modules
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containing statements like ::
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from modname import some_objects
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will continue to work with the old version of the imported objects. If the
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module contains class definitions, existing class instances will *not* be
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updated to use the new class definition. This can result in the following
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paradoxical behaviour::
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>>> import importlib
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>>> import cls
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>>> c = cls.C() # Create an instance of C
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>>> importlib.reload(cls)
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<module 'cls' from 'cls.py'>
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>>> isinstance(c, cls.C) # isinstance is false?!?
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False
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The nature of the problem is made clear if you print out the "identity" of the
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class objects::
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>>> hex(id(c.__class__))
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'0x7352a0'
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>>> hex(id(cls.C))
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'0x4198d0'
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