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Issue #10912: Clarify the documentation of PyObject_RichCompareBool. Thanks to Devin Jeanpierre for spotting the problem.

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Eli Bendersky 2011-01-15 10:23:34 +00:00
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Doc/c-api/object.rst
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@ -108,6 +108,9 @@ Object Protocol
Python expression ``o1 op o2``, where ``op`` is the operator corresponding to
*opid*.
.. note::
If *o1* and *o2* are the same object, :c:func:`PyObject_RichCompareBool`
will always return ``1`` for :const:`Py_EQ` and ``0`` for :const:`Py_NE`.
.. c:function:: PyObject* PyObject_Repr(PyObject *o)