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An empty argv-array is initialized to point to a static empty NULL-terminated array. The original implementation separates the actual storage of the NULL-terminator from the pointer to the list. This makes the exposed type a "const char **", which nicely matches the type stored by the argv-array. However, this indirection means that one cannot use empty_argv to initialize a static variable, since it is not a constant. Instead, we can expose empty_argv directly, as an array of pointers. The only place we use it is in the ARGV_ARRAY_INIT initializer, and it decays to a pointer appropriately there. Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
21 lines
464 B
C
21 lines
464 B
C
#ifndef ARGV_ARRAY_H
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#define ARGV_ARRAY_H
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extern const char *empty_argv[];
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struct argv_array {
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const char **argv;
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int argc;
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int alloc;
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};
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#define ARGV_ARRAY_INIT { empty_argv, 0, 0 }
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void argv_array_init(struct argv_array *);
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void argv_array_push(struct argv_array *, const char *);
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__attribute__((format (printf,2,3)))
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void argv_array_pushf(struct argv_array *, const char *fmt, ...);
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void argv_array_clear(struct argv_array *);
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#endif /* ARGV_ARRAY_H */
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