git/git-grep.sh
Linus Torvalds c0c35d5e41 Disallow empty pattern in "git grep"
For some reason I've done a "git grep" twice with no pattern, which is
really irritating, since it just grep everything. If I actually wanted
that, I could do "git grep ^" or something.

So add a "usage" message if the pattern is empty.

Signed-off-by: Linus Torvalds <torvalds@osdl.org>
Signed-off-by: Junio C Hamano <junkio@cox.net>
2005-11-16 13:17:46 -08:00

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#!/bin/sh
#
# Copyright (c) Linus Torvalds, 2005
#
pattern=
flags=()
git_flags=()
while : ; do
case "$1" in
--cached|--deleted|--others|--killed|\
--ignored|--exclude=*|\
--exclude-from=*|\--exclude-per-directory=*)
git_flags=("${git_flags[@]}" "$1")
;;
-e)
pattern="$2"
shift
;;
-A|-B|-C|-D|-d|-f|-m)
flags=("${flags[@]}" "$1" "$2")
shift
;;
--)
# The rest are git-ls-files paths (or flags)
shift
break
;;
-*)
flags=("${flags[@]}" "$1")
;;
*)
if [ -z "$pattern" ]; then
pattern="$1"
shift
fi
break
;;
esac
shift
done
[ "$pattern" ] || {
echo >&2 "usage: 'git grep <pattern> [pathspec*]'"
exit 1
}
git-ls-files -z "${git_flags[@]}" "$@" |
xargs -0 grep "${flags[@]}" -e "$pattern"