checkout-index: remove obsolete comment

The first paragraph about flag order is no longer true and is
mentioned in git-checkout-index.txt. The rest is also mentioned in
git-checkout-index.txt.

Remove it and keep uptodate document in one place.

Signed-off-by: Nguyễn Thái Ngọc Duy <pclouds@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Nguyễn Thái Ngọc Duy 2011-08-17 19:22:13 +07:00 committed by Junio C Hamano
parent 8499644ea7
commit a47a645e70

View file

@ -3,38 +3,6 @@
*
* Copyright (C) 2005 Linus Torvalds
*
* Careful: order of argument flags does matter. For example,
*
* git checkout-index -a -f file.c
*
* Will first check out all files listed in the cache (but not
* overwrite any old ones), and then force-checkout "file.c" a
* second time (ie that one _will_ overwrite any old contents
* with the same filename).
*
* Also, just doing "git checkout-index" does nothing. You probably
* meant "git checkout-index -a". And if you want to force it, you
* want "git checkout-index -f -a".
*
* Intuitiveness is not the goal here. Repeatability is. The
* reason for the "no arguments means no work" thing is that
* from scripts you are supposed to be able to do things like
*
* find . -name '*.h' -print0 | xargs -0 git checkout-index -f --
*
* or:
*
* find . -name '*.h' -print0 | git checkout-index -f -z --stdin
*
* which will force all existing *.h files to be replaced with
* their cached copies. If an empty command line implied "all",
* then this would force-refresh everything in the cache, which
* was not the point.
*
* Oh, and the "--" is just a good idea when you know the rest
* will be filenames. Just so that you wouldn't have a filename
* of "-a" causing problems (not possible in the above example,
* but get used to it in scripting!).
*/
#include "builtin.h"
#include "cache.h"