grep: use get_pathspec() correctly

When there is no remaining string in argv, get_pathspec(prefix, argv)
will return a two-element array that has prefix as the first element,
so there is no need to re-roll that logic in the code that uses
get_pathspec().

Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Junio C Hamano 2011-05-09 21:34:04 -07:00
parent b060ce7de4
commit 7c5f3cc4a5

View file

@ -956,13 +956,7 @@ int cmd_grep(int argc, const char **argv, const char *prefix)
verify_filename(prefix, argv[j]);
}
if (i < argc)
paths = get_pathspec(prefix, argv + i);
else if (prefix) {
paths = xcalloc(2, sizeof(const char *));
paths[0] = prefix;
paths[1] = NULL;
}
paths = get_pathspec(prefix, argv + i);
init_pathspec(&pathspec, paths);
pathspec.max_depth = opt.max_depth;
pathspec.recursive = 1;