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strbuf_humanise: use unsigned variables

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All of the numeric formatting done by this function uses
"%u", but we pass in a signed "int". The actual range
doesn't matter here, since the conditional makes sure we're
always showing reasonably small numbers. And even gcc's
format-checker does not seem to mind. But it's potentially
confusing to a reader of the code to see the mismatch.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2018-07-24 06:52:29 -04:00 committed by Junio C Hamano
parent 765b496dc6
commit 7726d360b5
1 changed files with 5 additions and 5 deletions
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10
strbuf.c
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@ -734,18 +734,18 @@ void strbuf_humanise_bytes(struct strbuf *buf, off_t bytes)
{
if (bytes > 1 << 30) {
strbuf_addf(buf, "%u.%2.2u GiB",
(int)(bytes >> 30),
(int)(bytes & ((1 << 30) - 1)) / 10737419);
(unsigned)(bytes >> 30),
(unsigned)(bytes & ((1 << 30) - 1)) / 10737419);
} else if (bytes > 1 << 20) {
int x = bytes + 5243; /* for rounding */
unsigned x = bytes + 5243; /* for rounding */
strbuf_addf(buf, "%u.%2.2u MiB",
x >> 20, ((x & ((1 << 20) - 1)) * 100) >> 20);
} else if (bytes > 1 << 10) {
int x = bytes + 5; /* for rounding */
unsigned x = bytes + 5; /* for rounding */
strbuf_addf(buf, "%u.%2.2u KiB",
x >> 10, ((x & ((1 << 10) - 1)) * 100) >> 10);
} else {
strbuf_addf(buf, "%u bytes", (int)bytes);
strbuf_addf(buf, "%u bytes", (unsigned)bytes);
}
}