Documentation/technical: avoid stray backslash in parse-options API docs

Due to some unpleasant interaction between the `quote', 'italics',
and `monospace` rules, a certain paragraph ends up rendered like so:

	‘short` is a character for the short option
	  (e.g. <tt>'e\’</tt> for <tt>-e</tt>, use <tt>0</tt> to omit),

Use the {apostrophe} to avoid this.

While at it, escape "->" strings: they are meant as a literal
two-character C operator, not a right-pointing arrow.

Reported-by: Frédéric Brière <fbriere@fbriere.net>
Signed-off-by: Jonathan Nieder <jrnieder@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jonathan Nieder 2010-08-20 05:32:36 -05:00 committed by Junio C Hamano
parent 12378c0aa8
commit 6dcca4d0ea

View file

@ -201,7 +201,7 @@ The last element of the array must be `OPT_END()`.
If not stated otherwise, interpret the arguments as follows:
* `short` is a character for the short option
(e.g. `\'e\'` for `-e`, use `0` to omit),
(e.g. `{apostrophe}e{apostrophe}` for `-e`, use `0` to omit),
* `long` is a string for the long option
(e.g. `"example"` for `\--example`, use `NULL` to omit),
@ -228,10 +228,10 @@ The function must be defined in this form:
The callback mechanism is as follows:
* Inside `func`, the only interesting member of the structure
given by `opt` is the void pointer `opt->value`.
`\*opt->value` will be the value that is saved into `var`, if you
given by `opt` is the void pointer `opt\->value`.
`\*opt\->value` will be the value that is saved into `var`, if you
use `OPT_CALLBACK()`.
For example, do `*(unsigned long *)opt->value = 42;` to get 42
For example, do `*(unsigned long *)opt\->value = 42;` to get 42
into an `unsigned long` variable.
* Return value `0` indicates success and non-zero return