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ref_transaction_commit(): work with transaction->updates in place

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Now that we free the transaction when we are done, there is no need to
make a copy of transaction->updates before working with it.

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Michael Haggerty 2014-04-07 15:48:18 +02:00 committed by Junio C Hamano
parent 84178db76f
commit 6a402338ec
1 changed files with 1 additions and 4 deletions
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5
refs.c
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@ -3413,19 +3413,17 @@ int ref_transaction_commit(struct ref_transaction *transaction,
const char *msg, enum action_on_err onerr)
{
int ret = 0, delnum = 0, i;
struct ref_update **updates;
const char **delnames;
int n = transaction->nr;
struct ref_update **updates = transaction->updates;
if (!n)
return 0;
/* Allocate work space */
updates = xmalloc(sizeof(*updates) * n);
delnames = xmalloc(sizeof(*delnames) * n);
/* Copy, sort, and reject duplicate refs */
memcpy(updates, transaction->updates, sizeof(*updates) * n);
qsort(updates, n, sizeof(*updates), ref_update_compare);
ret = ref_update_reject_duplicates(updates, n, onerr);
if (ret)
@ -3480,7 +3478,6 @@ int ref_transaction_commit(struct ref_transaction *transaction,
for (i = 0; i < n; i++)
if (updates[i]->lock)
unlock_ref(updates[i]->lock);
free(updates);
free(delnames);
ref_transaction_free(transaction);
return ret;