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alloc: write out allocator definitions
Because the allocator functions for tree, blobs, etc are all very similar, we originally used a macro to avoid repeating ourselves. Since the prior commit, though, the heavy lifting is done by an inline helper function. The macro does still save us a few lines, but at some readability cost. It obfuscates the function definitions (and makes them hard to find via grep). Much worse, though, is the fact that it isn't used consistently for all allocators. Somebody coming later may be tempted to modify DEFINE_ALLOCATOR, but they would miss alloc_commit_node, which is treated specially. Let's just drop the macro and write everything out explicitly. Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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parent
225ea22046
commit
600e2a69df
38
alloc.c
38
alloc.c
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@ -18,13 +18,6 @@
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#define BLOCKING 1024
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#define DEFINE_ALLOCATOR(name, type) \
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static struct alloc_state name##_state; \
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void *alloc_##name##_node(void) \
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{ \
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return alloc_node(&name##_state, sizeof(type)); \
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}
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union any_object {
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struct object object;
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struct blob blob;
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@ -55,10 +48,33 @@ static inline void *alloc_node(struct alloc_state *s, size_t node_size)
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return ret;
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}
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DEFINE_ALLOCATOR(blob, struct blob)
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DEFINE_ALLOCATOR(tree, struct tree)
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DEFINE_ALLOCATOR(tag, struct tag)
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DEFINE_ALLOCATOR(object, union any_object)
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static struct alloc_state blob_state;
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void *alloc_blob_node(void)
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{
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struct blob *b = alloc_node(&blob_state, sizeof(struct blob));
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return b;
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}
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static struct alloc_state tree_state;
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void *alloc_tree_node(void)
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{
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struct tree *t = alloc_node(&tree_state, sizeof(struct tree));
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return t;
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}
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static struct alloc_state tag_state;
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void *alloc_tag_node(void)
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{
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struct tag *t = alloc_node(&tag_state, sizeof(struct tag));
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return t;
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}
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static struct alloc_state object_state;
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void *alloc_object_node(void)
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{
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struct object *obj = alloc_node(&object_state, sizeof(union any_object));
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return obj;
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}
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static struct alloc_state commit_state;
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