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name-rev: avoid leaking memory in the deref
case
When the `name_rev()` function is asked to dereference the tip name, it allocates memory. But when it turns out that another tip already described the commit better than the current one, we forgot to release the memory. Pointed out by Coverity. Signed-off-by: Johannes Schindelin <johannes.schindelin@gmx.de> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -28,6 +28,7 @@ static void name_rev(struct commit *commit,
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struct rev_name *name = (struct rev_name *)commit->util;
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struct commit_list *parents;
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int parent_number = 1;
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char *to_free = NULL;
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parse_commit(commit);
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@ -35,7 +36,7 @@ static void name_rev(struct commit *commit,
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return;
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if (deref) {
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tip_name = xstrfmt("%s^0", tip_name);
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tip_name = to_free = xstrfmt("%s^0", tip_name);
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if (generation)
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die("generation: %d, but deref?", generation);
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@ -53,8 +54,10 @@ static void name_rev(struct commit *commit,
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name->taggerdate = taggerdate;
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name->generation = generation;
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name->distance = distance;
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} else
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} else {
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free(to_free);
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return;
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}
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for (parents = commit->parents;
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parents;
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