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expire_reflog(): return early if the reference has no reflog

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There is very little cleanup needed if the reference has no reflog. If
we move the initialization of log_file down a bit, there's even less.
So instead of jumping to the cleanup code at the end of the function,
just do the cleanup and return inline.

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Reviewed-by: Jonathan Nieder <jrnieder@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Michael Haggerty 2014-12-12 09:56:45 +01:00 committed by Junio C Hamano
parent 524127afbf
commit 2e376b3156
1 changed files with 5 additions and 3 deletions
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8
builtin/reflog.c
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@ -368,9 +368,11 @@ static int expire_reflog(const char *refname, const unsigned char *sha1,
lock = lock_any_ref_for_update(refname, sha1, 0, NULL);
if (!lock)
return error("cannot lock ref '%s'", refname);
if (!reflog_exists(refname)) {
unlock_ref(lock);
return 0;
}
log_file = git_pathdup("logs/%s", refname);
if (!reflog_exists(refname))
goto finish;
if (!cmd->dry_run) {
newlog_path = git_pathdup("logs/%s.lock", refname);
cb.newlog = fopen(newlog_path, "w");
@ -419,7 +421,7 @@ static int expire_reflog(const char *refname, const unsigned char *sha1,
clear_commit_marks(tip_commit, REACHABLE);
}
}
finish:
if (cb.newlog) {
if (fclose(cb.newlog)) {
status |= error("%s: %s", strerror(errno),