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builtin/show-ref: ensure mutual exclusiveness of subcommands
The git-show-ref(1) command has three different modes, of which one is implicit and the other two can be chosen explicitly by passing a flag. But while these modes are standalone and cause us to execute completely separate code paths, we gladly accept the case where a user asks for both `--exclude-existing` and `--verify` at the same time even though it is not obvious what will happen. Spoiler: we ignore `--verify` and execute the `--exclude-existing` mode. Let's explicitly detect this invalid usage and die in case both modes were requested. Signed-off-by: Patrick Steinhardt <ps@pks.im> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -275,6 +275,10 @@ int cmd_show_ref(int argc, const char **argv, const char *prefix)
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argc = parse_options(argc, argv, prefix, show_ref_options,
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argc = parse_options(argc, argv, prefix, show_ref_options,
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show_ref_usage, 0);
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show_ref_usage, 0);
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if ((!!exclude_existing_opts.enabled + !!verify) > 1)
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die(_("only one of '%s' or '%s' can be given"),
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"--exclude-existing", "--verify");
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if (exclude_existing_opts.enabled)
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if (exclude_existing_opts.enabled)
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return cmd_show_ref__exclude_existing(&exclude_existing_opts);
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return cmd_show_ref__exclude_existing(&exclude_existing_opts);
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else if (verify)
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else if (verify)
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@ -196,4 +196,13 @@ test_expect_success 'show-ref --verify with dangling ref' '
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)
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)
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'
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'
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test_expect_success 'show-ref sub-modes are mutually exclusive' '
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cat >expect <<-EOF &&
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fatal: only one of ${SQ}--exclude-existing${SQ} or ${SQ}--verify${SQ} can be given
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EOF
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test_must_fail git show-ref --verify --exclude-existing 2>err &&
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test_cmp expect err
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'
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test_done
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test_done
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