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bisect--helper: convert vocab_*
char pointers to char arrays
Instead of using a pointer that points at a constant string, just give name directly to the constant string; this way, we do not have to allocate a pointer variable in addition to the string we want to use. Let's convert `vocab_bad` and `vocab_good` char pointers to char arrays. Mentored-by: Christian Couder <chriscool@tuxfamily.org> Signed-off-by: Miriam Rubio <mirucam@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -52,8 +52,8 @@ static void set_terms(struct bisect_terms *terms, const char *bad,
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terms->term_bad = xstrdup(bad);
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}
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static const char *vocab_bad = "bad|new";
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static const char *vocab_good = "good|old";
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static const char vocab_bad[] = "bad|new";
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static const char vocab_good[] = "good|old";
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/*
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* Check whether the string `term` belongs to the set of strings
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